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Orlov [11]
3 years ago
9

$1

Mathematics
2 answers:
Kryger [21]3 years ago
8 0

Answer:

$1 dollar split into the ratio 1:3 is 0.25:0.75. Is that what you're looking for?

ELEN [110]3 years ago
3 0
1?????????????????????
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Show the expression as the base to one power. 4^5⋅4^3
White raven [17]
Hey there! :D

When you multiply powers, you add them.

You would only need to add 5 and 3 together. 

5+3= 8

4^8 <=== the answer

I hope this helps! 
~kaikers 
5 0
4 years ago
Can u please answer this .
frutty [35]
G=n/5 should represent the amount of gallons of sauce needed per pizza
6 0
3 years ago
Find the value of b. Express the answer as a simplified radical.
Mama L [17]

Here three sides of a right angled triangle given.

The three sides are b, 8 and 14.

The side with length 14 is the hypotenuse here. We have to find the side of length b.

To get b, we will use Pythagoras theorem here.

By using Pythagoras theorem we can write,

c^2=a^2+b^2, where c is the hypotenuse.

So here we can write,

14^2=8^2+b^2

196 = 8^2+b^2

196=64+b^2

To solve it for b, now we have to move 64 to the left side by subtracting it from both sides.

196-64 = 64+b^2-64

196-64 = b^2

132=b^2

Now to find b, we have to take square root to both sides. We will get,

\sqrt{132}= \sqrt{b^2}

\sqrt{132} =b

b= \sqrt{(4)(33)}

b= (\sqrt{4})(\sqrt{33})

b= 2\sqrt{33}

We have got the required answer for the side b.

6 0
3 years ago
Read 2 more answers
This is not a question i just need someone to make sure i did #16 right. Thanks;)
Lapatulllka [165]
I think the length of pool in inches is actually 12*12=144 because there are 12 inches in a foot.
Also, the scale factor would be 144/16 = 9.
5 0
3 years ago
Read 2 more answers
Plz explain and prove the triangles congruence.
amm1812

Answer:

ΔNAS≅ΔSEN by SSA axiom of congruency.

Step-by-step explanation:

Consider ΔNAS and ΔSEN,

NS=SN(Common ie . Both are the same side)

SA=NE( Given in the question that SA≅ NE)

∠SNA=∠NSE( Due to corresponding angle property where SE ║ NA)

Therefore, ΔNAS ≅ΔSEN by SSA axiom of congruency.

∴ NA≅SA by congruent parts of congruent Δ. Hence, proved.

8 0
3 years ago
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