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2 years ago

May I please receive help?

Mathematics

2 answers:

ELEN [110]2 years ago

6 0

Step-by-step explanation:

Apply Pythagoren Theorem.

${x}^{2} + {y}^{2} = {c}^{2}$

where x and y is the legs (the sides that form a right triangle) and c is the hypotenuse.

the legs are 6 and our unknown. so let x represent the unknown

${6}^{2} + {x}^{2} = {11}^{2}$

$36 + {x}^{2} = 121$

${x}^{2} = 85$

$x = \sqrt{85}$

x=9.2

Yuki888 [10]2 years ago

3 0

Answer:

9.2 ft

Step-by-step explanation:

The shape is a triangle, the 11 ft is your hypotenuse

You need to use the Pythagorean Theorem!

a^2 + b^2 = c^2 (solve for a, the missing length that they ask for)

so --->

a^2 + (6^2) = 11^2

a^2 + 36 = 121

~subtract 36 to the right side~

a^2 = 85

now find the square root of 85:

a = 9.21954

round it to the nearest tenth:

a = 9.2

final answer: 9.2 ft

hope this helpsss

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3 years ago

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Lerok [7]

Answer:

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Step-by-step explanation:

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3 years ago

BD is the angle bisector of

AlexFokin [52]

Note: Let us consider, we need to find the $m\angle ABC$ and $m\angle DBC$ .

Given:

In the given figure, BD is the angle bisector of ABC.

To find:

The $m\angle ABC$ and $m\angle DBC$ .

Solution:

BD is the angle bisector of ABC. So,

$m\angle ABD=m\angle DBC$

$3x=x+20$

$3x-x=20$

$2x=20$

Divide both sides by 2.

$x=\dfrac{20}{2}$

$x=10$

Now,

$m\angle DBC=(x+20)^\circ$

$m\angle DBC=(10+20)^\circ$

$m\angle DBC=30^\circ$

And,

$m\angle ABC=(3x)^\circ+(x+20)^\circ$

$m\angle ABC=(4x+20)^\circ$

$m\angle ABC=(4(10)+20)^\circ$

$m\angle ABC=(40+20)^\circ$

$m\angle ABC=60^\circ$

Therefore, $m\angle DBC=30^\circ,m\angle ABD=30^\circ$ and $m\angle ABC=60^\circ$ .

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2 years ago

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brilliants [131]

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3 years ago

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Answer

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