Answer a is 14.40 the discount price is 14.40
The distance between points M(6,16) and Z(-1,14) to the nearest tenth is 5.4 units.
The formula for calculating the distance between two points is expressed as:
![D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\](https://tex.z-dn.net/?f=D%20%3D%20%5Csqrt%7B%28x_2-x_1%29%5E2%2B%28y_2-y_1%29%5E2%7D%20%5C%5C)
Given the coordinates M(6,16) and Z(-1,14)
Substitute the given coordinates into the formula
![D = \sqrt{(-1-6)^2+(14-16)^2} \\D =\sqrt{(-5)^2+(-2)^2}\\D=\sqrt{25+4}\\D=\sqrt{29}\\D = 5.38\\D \approx 5.4 units](https://tex.z-dn.net/?f=D%20%3D%20%5Csqrt%7B%28-1-6%29%5E2%2B%2814-16%29%5E2%7D%20%5C%5CD%20%3D%5Csqrt%7B%28-5%29%5E2%2B%28-2%29%5E2%7D%5C%5CD%3D%5Csqrt%7B25%2B4%7D%5C%5CD%3D%5Csqrt%7B29%7D%5C%5CD%20%3D%20%20%20%205.38%5C%5CD%20%5Capprox%205.4%20units)
Hence the distance between points M(6,16) and Z(-1,14) to the nearest tenth is 5.4 units.
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Answer:
Step-by-step explanation:
Its about 42.67
Answer:
In 1979 the amount of transistors in a chip was approximately 27865.
Step-by-step explanation:
Since the number of transistors in 1974 was 5000 per chip and it increases at a rate of 41% per year, the number of transistors in a chip per year can be modelled by the following expression:
chips(t) = 5000*(1.41)^(t - 1974)
Therefore in 1979, we have:
chips(1979) = 5000*(1.41)^(1979 - 1974)
chips(1979) = 5000*(1.41)^5
chips(1979) = 27865.4183
In 1979 the amount of transistors in a chip was approximately 27865.
Answer:
1 1/2
Step-by-step explanation:
hope this helps boo