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Andrews [41]
3 years ago
10

Evaluate the expression when c = -2 and y = 7. c-2y

Mathematics
1 answer:
stepan [7]3 years ago
5 0

Step-by-step explanation:

The answer to the question is -14

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Evaluate expression 8s-5t+s2;s=4,t=1
jeka57 [31]
8(4)-5(1)+2(4)
Multiply
32-5+8
Solve from left to right
28+8
36

The answer is 36
4 0
3 years ago
Angie divides the polynomial function f(x)=x3+3x2−7x−21 by (x + 3). What can she conclude from the fact that the remainder is eq
iren [92.7K]

Answer:

See below

Step-by-step explanation:

<u>Given function</u>

  • f(x)=x³ + 3x²- 7x - 21

<u>We can find its factors:</u>

  • x³ + 3x² - 7x - 21 =
  • x²(x + 3) - 7(x + 3) =
  • (x² - 7)(x + 3)

We can conclude that the given polynomial function is fully divisible by (x + 3) and the quotient is (x² - 7)

Also one of zeros of the function is -3

8 0
3 years ago
Given the following table, determine the missing value.
sergeinik [125]
We know that
Based on the table
Percent%=[1-Decay factor]*100%
so

for decay factor=0.98
Percent%=[1-0.98]*100%----> 2%

for decay factor=0.50
Percent%=[1-0.50]*100%---->50 %

for decay factor=0.64
Percent%=[1-0.64]*100%----> 36%

for decay factor=0.23
Percent%=[1-0.23]*100%----> 77%

therefore

the answer is
36%

6 0
3 years ago
What is the missing reason in Step 8? 
Lynna [10]
The missing reason is you didn't put the actual question on here.

please show the full question. 
4 0
3 years ago
The ball used in a soccer game may not weigh more than 16 ounces or less
Liono4ka [1.6K]
In order for the ball to be used in the game, it must be able to meet the minimum and maximum weight requirements. These are the limits of the weight of the ball. If it exceeds the maximum limit of 16 ounces or below the minimum limit of 14 ounces, the ball will not be approved.

So, by adding 1.5 ounces, that would mean that the initial weight of the ball did not reach the minimum limit. The initial weight of the ball, denoted as x, have two possible values. The first value is the initial weight plus added with 1.5 ounces would reach 14 ounces.

x + 1.5 = 14
x = 12.5 ounces

The other scenario is when the initial weight is added to reach the maximum requirement of 16 ounces

x + 1.5 = 16
x = 14.5 ounces

From both answer, we could conclude that the initial weight has to be 12.5 ounces. If the initial weight were 14.5 ounces to begin with, there should be no need for air. It cans till be approved to be used.
3 0
3 years ago
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