The answer is he left at 8:55 because if you add 10 min to that and thats 9:05 then add 25 more min it would be 9:30
- <u>Jan </u><u>purchased </u><u>1</u><u>4</u><u>0</u><u> </u><u>shares </u><u>of </u><u>stock </u><u>in </u><u>ABC </u><u>company </u><u>at </u><u>a </u><u>price </u><u>of </u><u>$</u><u>1</u><u>8</u><u>.</u><u>7</u><u>5</u><u> </u><u>per </u><u>share </u>
- <u>During </u><u>the </u><u>next </u><u>3</u><u> </u><u>days</u><u>, </u><u> </u><u>the </u><u>value </u><u>of </u><u>share </u><u>declined </u><u>by </u><u>$</u><u>1</u><u>.</u><u>0</u><u>0</u><u> </u><u>,</u><u> </u><u>$</u><u>1</u><u>.</u><u>7</u><u>5</u><u> </u><u>and </u><u>$</u><u>1</u><u>.</u><u>5</u><u>0</u>
- <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>a </u><u>share </u><u>of </u><u>ABC </u><u>stock </u><u>at </u><u>the </u><u>end </u><u>of </u><u>3</u><u> </u><u>days </u>
<u>According </u><u>to </u><u>the </u><u>question</u><u>, </u>
Cost of 1 share of ABC company = $18.75
<u>Therefore</u><u>, </u>
Cost of 140 shares purchased by Jan in the ABC company
<u>Now</u><u>, </u>
For next 3 days, the value of share declined
<u>Therefore</u><u>, </u>
The value of shares after 3 days will be
Hence, The value of share after 3 days will be $18.75 .
Answer:
Step-by-step explanation:
Comparing the given y-4=-2/5(x-1) with the standard point-slope formula for the equation of a straight line, we get
y-4=-2/5(x-1)
y-k = (-2/5)(x - 1). Thus, k = 4 and h = 1, and so one point on this new line is (1, 4).
The slope is -2/5.
First, plot a dark dot at (1, 4).
Next, starting with your pencil point on that dot, move your point 5 units to the right and then 2 units down. Plot a dark dot there.
Finally, draw a line through your two dark dots.
From the Quotient-Remainder Theorem follows that for every f(x) there exist unique polynomials q(x) and r(x) such that:
,
where r(x) is called remainder.
If r(x)=0, then f(x)=h(x)q(x) and q(x) is adivisor. If q(x) is of form q(x)=x-a, then a is a root of f(x).