Question

I'm still confused on solving equation! could you help do this?

Answer 1

$\frac{1}{2} x - 3 = \frac{2}{3} (x-1) \\ \\\frac{1}{2} x - 3 = \frac{2}{3}x-\frac{2}{3} \\ \\\frac{2}{3} - 3 = \frac{2}{3}x- \frac{1}{2} x \\ \\\frac{2}{3} - \frac{9}{3} = \frac{2*2}{3*2}x- \frac{1*3}{2*3} x\\ \\-\frac{7}{3} =\frac{1}{6} x \\ \\-\frac{7}{3}*6 =\frac{1}{6} x*6 \\ \\ x=-14$

Answer 2

$\dfrac{1}{2} x-3=\dfrac{2}{3}(x-1)|\cdot6\\ 3x-18=4(x-1)\\ 3x-18=4x-4\\ 4x-3x=-18+4\\ x=-14$