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nordsb [41]
3 years ago
13

I need to know how to be able to solve this

Mathematics
1 answer:
arsen [322]3 years ago
5 0

Answer:

The absolute value of x is thus always either positive or zero, but never negative: when x itself is negative (x < 0), then its absolute value is necessarily positive (|x| = −x > 0)

Step-by-step explanation:

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Which Question Has roots of x= -2 and x
vazorg [7]

See explanation below.

Explanation:

The 'difference between roots and factors of an equation' is not a straightforward question. Let's define both to establish the link between the two..

Assume we have some function of a single variable

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Now, up to this point we have not assumed anything about

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=

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4 0
2 years ago
What are the correct classifications for the polygon
Dmitry [639]
It’s convex hexagon
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What is the simplified answer to 5+3w+3-w​
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<h2>5 + 3w + 3 - w = 2w + 8</h2>

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5+3w+3-w\qquad\text{combine like terms}\\\\=(3w-w)+(5+3)\\\\=2w+8

6 0
3 years ago
Write a two-column proof. Given: line BD bisects angle CBE. Prove: angle ABD approximately equal to angle FBD.
ale4655 [162]

Answer:

The proof is derived from the summarily following equations;

∠FBE + ∠EBD = ∠CBA + ∠CBD

∠FBE + ∠EBD = ∠FBD

∠CBA + ∠CBD = ∠ABD

Therefore;

∠ABD ≅ ∠FBD

Step-by-step explanation:

The two column proof is given as follows;

Statement {}                                       Reason          

\underset{BD}{\rightarrow} bisects ∠CBE {}                            Given

Therefore;

∠EBD ≅ ∠CBD  {}                              Definition of angle bisector

∠FBE ≅ ∠CBA {}                                Vertically opposite angles are congruent

Therefore, we have;

∠FBE + ∠EBD = ∠CBA + ∠CBD {}     Transitive property

∠FBE + ∠EBD = ∠FBD {}                    Angle addition postulate

∠CBA + ∠CBD = ∠ABD {}                   Angle addition postulate

Therefore;

∠ABD ≅ ∠FBD        {}                          Transitive property.

3 0
2 years ago
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