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Lady_Fox [76]
3 years ago
9

How would i use the LCD of 10 to solve 3/15 + 5/15 ?​

Mathematics
1 answer:
Lady_Fox [76]3 years ago
7 0

Answer:

8/15

Step-by-step explanation:

3/15+5/15=8/15

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What is the least common multiple of 96 144 and 224
Gennadij [26K]
The least common multiple of 96, 144, and 224 is 2016.

Hope this helps! :D
5 0
3 years ago
Read 2 more answers
Okay this is my last one.. I think dfghmhgfd
Ainat [17]
<h2>○=> <u>Correct option</u> :</h2><h2>\color{plum}\tt\bold{(B)}</h2><h3>○=> <u>Steps to derive correct option</u> :</h3>

We know that :

\color{hotpink} \tt \: circumference \: of \: a \: circle\color{plum} = 2\pi r

So, let the diameter of this circle be x.

Which means :

=\tt2  \times \pi  \times r

=\tt 2 \times x \times \pi = 12\pi

=\tt 2x\pi = 12\pi

=\tt x =  \frac{12}{2}

= \tt \: x = 6 \: m

Thus, the radius of the circle Robert drew = 6 m

Since the circle in option B has a radius of 6 m, it is the circle Robert drew.

▪︎<em>Therefore, the correct option is (B)</em>

8 0
2 years ago
Y= 0.26x + 4.4*10^-4
Temka [501]

Y= 0.26x+4.4*10^-4

Y= 0.26x+4.4*10,000

Y=0.26x+44,000


I'm not sure if you were only trying to simplify the problem, but I hope this helped

6 0
3 years ago
What is the answer to -6 2/3 - -8 1/5
zvonat [6]
14 2/8 should probably be your answear
7 0
3 years ago
A bag contains 3 red, 4 blue, and 6 yellow marbles. One marble is selected at a time, and once a marble is selected, it is not r
astraxan [27]

The probability of choosing two yellow marbles = 5/26

Step-by-step explanation:

Step 1 :

Given

Total number of marbles in the bag = 13 marbles

Number of yellow marbles = 6.

We choose 2 marbles from the bag without replacing and need to determine the probability that both are yellow.

Step 2 :

Probability of finding yellow marble in the first try = Number of yellow marbles / Total number of marbles = \frac{6}{13}

Once the yellow marble is selected we have 5 yellow marbles among 12 remaining marbles in the bag.

Probability of finding yellow marble in the second try = Number of yellow marbles / Total number of marbles = \frac{5}{12}

Step 3:

P(yellow in first 2 tries) = P(yellow in first try) * P(yellow in second try)

P(yellow in first 2 tries) = \frac{6}{13} * \frac{5}{12} = \frac{5}{26}

Step 4:

Answer:

The probability of choosing two yellow marbles = 5/26

4 0
3 years ago
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