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sweet [91]
3 years ago
8

Analyze the photo below and answer the question that follows.

Geography
2 answers:
Natali [406]3 years ago
3 0

Answer:

D. Russia

Explanation:

Moscow is the capital of Russia, so the Red Square is in Russia.

FromTheMoon [43]3 years ago
3 0
Moscow, in Russia. Hope that helps!
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The currents would travel all the way around the earth parallel to the equator
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11 What are TWO environmental advantages of
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Explanation:

11 What are TWO environmental advantages of

building a high-density development?

<u>D. Landscaping after the development is built helps</u>

<u>D. Landscaping after the development is built helpsoffset the environmental impact.</u>

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2 years ago
Compare the standard of living in Greenland to the standard of living in the United states.
aleksley [76]

Answer:

I'd say they both have a difference on how they run things, but that doesn't mean the countries are horrible, they do things differently in ways that people who live there want to stay there.

Explanation:

Consumer Prices in Greenland are 65.19% higher than in United States (without rent)

Consumer Prices Including Rent in Greenland are 42.22% higher than in United States

Rent Prices in Greenland are 1.99% lower than in United States

Restaurant Prices in Greenland are 30.19% higher than in United States

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7 0
3 years ago
a rural kansas watershed that is ungauged has an area of 475 acres and a main channel length of 6870 feet with an average slope
dlinn [17]

Answer:

\mathbf{Q_p  =682 \ \  ft^3/s}

Explanation:

Given that:

Area = 475 acres

The length of the channel (L) = 6870 feet

The average water shield slope (S) = 100 feet/mile

Since; 1 mile = 5280 feet

Burst duration D = 15 min

∴

100 feet/mile = 100/5280

The average water shield slope (S) = 5/264

Using hydrograph method:

The time of concentration t_c = 0.0078L^{0.77} S^{-0.385}

where;

L = 6870

S = 5/264

t_c = 0.0078(6870)^{0.77} (\dfrac{5}{264})^{-0.385}

t_c =32.34 min

Since 60 min = 1 hour

32.34 min will be (32.34*1)/60

= 0.539 hour

Lag time T_l = 0.67\times t_c

T_l = 0.67\times 32.34

T_l = 21.6678\ min

The time to peak i.e

T_p = \dfrac{D}{2}+ T_L \\ \\  T_p = \dfrac{15}{2}+ 21.6678 \\ \\  T_p = 29.168 \ min

T_r = \dfrac{T_p}{5.5} \\ \\  T_r = \dfrac{29.1678}{5.5} \\ \\ T_r = 5.30 \ min

Since D = 15 min is not equal to T_r, then we hydrograph apart from T_r duration lag time.

Then;

T_p \ ' = T_p + \dfrac{D-t_r}{4} \\ \\ T_p \ ' = 29.168 + \dfrac{15-5.30}{4} \\ \\ T_p \ ' = 31.593

Now, we need to determine the peak discharge Q_p by using the formula:

Q_p  = \dfrac{484 \times A}{T_p \ '}

where

484 = peak factor

Recall that A = 475 acres, to miles, we have:

A = 0.7422 mile²

T_p \ ' = 31.593/60

∴

Q_p  = \dfrac{484 \times 0.7422}{\dfrac{31.593}{60}}

\mathbf{Q_p  =682 \ \  ft^3/s}

7 0
3 years ago
Explica relaciones que existen entre la sociedad y la cultura
arsen [322]
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4 0
3 years ago
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