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natulia [17]
3 years ago
5

translate the phrase:""Three times the difference of a number and 9" " into an algebraic expression .Let x represent the real nu

mber...
Mathematics
1 answer:
erastovalidia [21]3 years ago
6 0
3(x-9) that is the answer to this one.
You might be interested in
A x 4 = E
lana [24]
A * 4 = E........A = E / 4
B / 4 = E........B = 4E
C + 4 = E......C = E - 4
D - 4 = E.......D = E + 4

A + B + C + D = 100
(E/4) + (4E) + (E - 4) + (E + 4) = 100
E/4 + 6E = 100 ....multiply by 4
E + 24E = 400
25E = 400
E = 400/25
E = 16 <===


7 0
3 years ago
80% of an airline's flights depart on-time and 20% do not. Of those that depart on-time, 95% arrive on-time. Of those that depar
Dmitry_Shevchenko [17]

Answer:

0.78

Step-by-step explanation:

given that 80% of an airline's flights depart on-time and 20% do not.

Of those that depart on-time, 95% arrive on-time. Of those that depart late, 10% arrive on-time

Let A be the event that flight departs on time.

Now A and A' are mutually exclusive and exhaustive

Let B be the event the flight arrives on time

Using total probability calculation we have

the chance of someone taking a flight that will arrive on-time

= P(B)

=P(A)+P(A'B)\\= 0.80(0.95) +0.20(0.10)\\= 0.76+0.02\\=0.78

4 0
3 years ago
Please help me, i need to turn it in today!!!
hodyreva [135]
Could you type the question, please.
8 0
2 years ago
Which ordered pair is a solution to the system of linear equations -4x+y=8 and x-5y=17 ?
Nastasia [14]

Answer:

(-3,-4)

Step-by-step explanation:

6 0
2 years ago
A psychologist is interested in knowing whether adults who were bullied as children differ from the general population in terms
MissTica

Answer:

t = \frac{39.5-30.6}{\frac{6.6}{\sqrt{25}}}= 6.74

The degrees of freedom are given by:

df =n-1= 25-1=24

Now we can calculate the p value with the following probability:

p_v = 2*P(t_{24}>6.74)= 5.69x10^{-7}

And for this case since the p value is lower compared to the significance level \alpha=0.05 we can reject the null hypothesis and we can conclude that the true mean for this case is different from 30.6 at the significance level of 0.05

Step-by-step explanation:

For this case we have the following info given:

\bar X = 39.5 represent the sample mean

s =6.6 represent the sample deviation

\mu = 30.6 represent the reference value to test.

n = 25 represent the sample size selected

The statistic for this case is given by:

t =\frac{\bar X -\mu}{\frac{s}{\sqrt{n}}}

And replacing we got:

t = \frac{39.5-30.6}{\frac{6.6}{\sqrt{25}}}= 6.74

The degrees of freedom are given by:

df =n-1= 25-1=24

Now we can calculate the p value with the following probability:

p_v = 2*P(t_{24}>6.74)= 5.69x10^{-7}

And for this case since the p value is lower compared to the significance level \alpha=0.05 we can reject the null hypothesis and we can conclude that the true mean for this case is different from 30.6 at the significance level of 0.05

3 0
3 years ago
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