A * 4 = E........A = E / 4
B / 4 = E........B = 4E
C + 4 = E......C = E - 4
D - 4 = E.......D = E + 4
A + B + C + D = 100
(E/4) + (4E) + (E - 4) + (E + 4) = 100
E/4 + 6E = 100 ....multiply by 4
E + 24E = 400
25E = 400
E = 400/25
E = 16 <===
Answer:
0.78
Step-by-step explanation:
given that 80% of an airline's flights depart on-time and 20% do not.
Of those that depart on-time, 95% arrive on-time. Of those that depart late, 10% arrive on-time
Let A be the event that flight departs on time.
Now A and A' are mutually exclusive and exhaustive
Let B be the event the flight arrives on time
Using total probability calculation we have
the chance of someone taking a flight that will arrive on-time
= P(B)
=
Could you type the question, please.
Answer:
(-3,-4)
Step-by-step explanation:
Answer:

The degrees of freedom are given by:
Now we can calculate the p value with the following probability:

And for this case since the p value is lower compared to the significance level
we can reject the null hypothesis and we can conclude that the true mean for this case is different from 30.6 at the significance level of 0.05
Step-by-step explanation:
For this case we have the following info given:
represent the sample mean
represent the sample deviation
represent the reference value to test.
represent the sample size selected
The statistic for this case is given by:

And replacing we got:

The degrees of freedom are given by:
Now we can calculate the p value with the following probability:

And for this case since the p value is lower compared to the significance level
we can reject the null hypothesis and we can conclude that the true mean for this case is different from 30.6 at the significance level of 0.05