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Viktor [21]
3 years ago
13

15 divided by what equals 5

Mathematics
2 answers:
mafiozo [28]3 years ago
6 0

Answer:

3

Step-by-step explanation:

imagine theres 15 people, and you have to make groups of 5, you will end up with 3 groups

gregori [183]3 years ago
3 0

Answer:3

Step-by-step explanation:

cause 15-3-3-3-3-3 has 5 3's

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Which of the following represents the diameter of the circle below?
Svetach [21]

Answer:

xy represents the diameter

7 0
2 years ago
Dr. Potter provides vaccinations against polio and measles. Each polio vaccination consists of 444 doses, and each measles vacci
nataly862011 [7]

Answer:

37 polio vaccinations and 23 measles vaccination.

Step-by-step explanation:

Let the number of polio vaccination given=x

Let the number of measles vaccination given=y

Dr. Potter gave a total of 60 vaccinations

x+y=60

Since each polio vaccination consists of 4 doses, and each measles vaccination consists of 2 doses. A total of 184 doses was given out.

4x+2y=184

To find the values of x and y, we solve the two equations simultaneously.

x+y=60             (1)

4x+2y=184        (2)

From (1), x=60-y

Substitute x=60-y into equation 2.

4x+2y=184

4(60-y)+2y=184

240-4y+2y=184

240-184=4y-2y

56=2y

Divode both sides by 2

y=23

Recall earlier that x=60-y

x=60-23=37

Dr Potter gave 37 polio vaccinations and 23 measles vaccination.

6 0
3 years ago
HELPPPP
satela [25.4K]

Answer:

the answer would be x(f)-3

Step-by-step explanation:

you already know

4 0
2 years ago
In an examination , ten students scored the following marks : 60 , 58 , 90 , 51 , 47 , 81 , 70 , 95 , 87 , 99.
Feliz [49]

Answer:

Range = highest data - lowest data

99-47=

52

5 0
3 years ago
Find the sum of the infinite series 1/3+4/9+16/27+64/81+.... if it exists.
pshichka [43]
9/27, 12/27, 16/27

So this is a geometric sequence as each term is 4/3 the previous term.

Since the common ration is greater than one the sum of the series diverges, it does not exist.  (The sum just keeps getting larger and larger)

For a geometric series to have a sum r^2<1

So that the normal sum....

s(n)=a(1-r^n)/(1-r)   becomes if r^2<1

s=a/(1-r)
6 0
3 years ago
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