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marysya [2.9K]
3 years ago
8

Dalton believed that:

Chemistry
1 answer:
Doss [256]3 years ago
5 0
The correct answer is C.atoms are divisible
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Are two double bonds in<br> uble dash.<br> :0=C=O<br> NO2-
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Yes

Explanation:

There are in double dash :) ( = )

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Explain why the two argon atoms are attracted<br> to each other.
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Each are non-metals, which form a covalent bond. They also have high electron rapport.
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3 years ago
How reliable is the perfect gas law in comparison with the van der waals equation?calculate the difference in pressure of 10.00g
Semmy [17]

Answer:

The perfect gas law is reliable at the limit of pressure tending to zero. That is to say, at low pressure. The Van der Waals law instead can be used at higher pressures.

Explanation:

The perfect law equation is

P.V = n.R.T

The perfect gas law considers that the gas molecules have no interaction between each other and each molecule has null volume. This condition happens at the limit of pressure tending to zero.

The Van der Waals equation is

(P +\frac{n^{2}.a}{V^{2}})(V-n.b) = n.R.T

On the other hand, the Van der Waals law has two extra terms, one to consider the interaction of the molecules (n2a/V2) and other to consider the volume of the molecules (V-nb). These terms make a better approximation to a real gas.

Using the two equations to calculate the pressure (P) for CO2 with

<em>V = 100cm3 = 0.1L</em>

<em>T = 25ºC = 298K</em>

<em>n = 10g/(44g/mol) = 0.23mol</em>

<em>a = 3.658 atm.L2/mol2</em>

<em>b = 0.0429 L/mol</em>

With the perfect law equation:

P = \frac{n.R.T}{V} = \frac{0.23molx0.082\frac{atm.L}{K.mol}x298K }{0.1L} = 56.2atm

With the Van del Waals law:

P = \frac{n.R.T}{V-n.b} -\frac{n^{2}.a}{V^{2} }

P = \frac{0.23molx0.082\frac{atm.L}{K.mol}x298K}{0.1L - 0.23molx0.0429\frac{L}{mol} }-\frac{(0.23mol)^{2}x3.658\frac{atm.L^{2}}{mol^{2}}}{(0.1L)^{2}} = 43 atm

At this case the difference between the results of the two equations is due to the big mass of CO2 which produce a high pressure.

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3 years ago
Non-examples of weather fronts.
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Many fronts cause weather events such as rain, thunderstorms, gusty winds, and tornadoes. At a cold front, there may be dramatic thunderstorms. At a warm front, there may be low stratus clouds. Usually, the skies clear once the front has passed.

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