Answer: 94.07%
Explanation:
Percentage yield can be calculated by the formula
%yield = Experimental yield/Theoretical yield x100
Experimental yield = 7.93g
Theoretical yield = 8.43
%yield = Experimental yield/Theoretical yield x100
%yield = 7.93/8.43 x 100 = 94.07%
Carbon dioxide leaves as a product of respiration
Answer:
the empirical (lowest raios) is
C2H4Cl
Explanation:
A compound is known to consist solely of carbon, hydrogen, and chlorine. Through elemental analysis, it was determined that the compound is composed of 24.27% carbon.
What is the empirical formula of this compound?
the compound has ONLY C, H, and Cl
the % Cl = 100% - 24.27% -4.03% = 71.7%
in 100 gm, there are 71.7 gm Cl, 24.27 gm C, and 4.03 gm H
the number of moles are Cl=71.7/70.91 =1.01= ~ 1
C = 24.27/12.0 = 2.02 =~ 2
H = 403/1.01 = 3.97 =~ 4
so the empirical (lowest raios) is
C2H4Cl
Answer:
See explanation
Explanation:
Step 1: Data given
For the reaction aA + bB ⇆ cC + dD
Kc = [C]^c * [D]^d / [A]^a [B]^b
a. SbCl5(g) ⇄ SbCl3(g) + Cl2(g)
Kc = [Cl2]*[SbCl3] / [SbCl5]
b. 2 BrNO(g) ⇄ 2NO(g) + Br2(g)
Kc = [Br2]*[NO]² / [BrNO]²
c. CH4(g) + 2 H2S(g) ⇄ CS2(g) + 4 H2(g)
Kc = [H2]^41 * [CS2] / [H2S]²*[CH4]
d. 2CO(g) + O2(g) ⇄ 2CO2(g)
Kc = [CO2]² / [O2][CO]²
