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AlekseyPX
4 years ago
9

1/x+a=b, solve for x. im lost​

Mathematics
1 answer:
mina [271]4 years ago
7 0

Answer:

Step-by-step explanation:

First, Let's take a on both sides:

\frac{1}{x}+a-a=b-a

\frac{1}{x}=b-a

Remember that 1/x is called the reciprocal. For example the reciprocal of 2 is 1/2 and the reciprocal of 5 is 1/5. If we read the equation is telling us: "Reciprocal of x is b - a". Therefore, \frac{1}{b-a}=x.

Another way to solve it is to multiply x on both sides. Then,

\frac{x}{x}=(b-a)*x

1=(b-a)*x

Then divide by (b-a). Remmebre to treat b-a as a factor:

\frac{1}{(b-a)}=\frac{(b-a)*x}{(b-a)}

Cancelling (b-a) on the right hand side:

\frac{1}{(b-a)}=x

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