Ask question

Ask question

All categories

3 years ago

5

The metro theater has 20 rows of seats with 18 Seats in each row. The theaters income in dollars if all seats are sold is (20x18

) x5. Use properties to find the total income

1 answer:

quester [9]3 years ago

4 0

It would be $1,800
You would use the distributive property to do 18x5 and then 20x5 and then add those to get 1,800

You might be interested in

The gym teacher has $250 to spend on volleyball equipment. She buys 4 volleyball nets for $28 each. Volleyballs cost $7 each. Ho

pav-90 [236]

Answer:

The maximum number of volleyballs that she can buy is 19

Step-by-step explanation:

Let

x ----> the number of volleyballs

we know that

The cost of each volleyball net ($28) by the number of volleyball nets (4) plus the cost of each volleyball ($7) multiplied by the number of volleyballs (x) must be less than or equal to $250

so

The inequality that represent this situation is

$28(4)+7x\leq 250$

Solve for x

$112+7x\leq 250$

subtract 112 both sides

$7x\leq 250-112$

$7x\leq 138$

Divide by 7 both sides

$x\leq 19.7$

therefore

The maximum number of volleyballs that she can buy is 19

4 0

3 years ago

2(m-3)+7<21 PLEASE HELP!!!

Contact [7]

Simplify. Distribute 2 to all terms within the parenthesis

2(m -3) = 2m - 6

Simplify. Combine like terms

2m - 6 + 7 < 21

2m + 1 < 21

Isolate the m. Subtract 1 from both sides

2m + 1 (-1) < 21 (-1)

2m < 20

Isolate the m. Divide 2 from both sides

2m/2 < 20/2

m < 20/2

m < 10

m < 10 is your answer

hope this helps

4 0

3 years ago

2/3, 24%, 0.61 least to greasiest

Semmy [17]

24% .61 2/3 two thirds is .66 24% is .24 and .61 is .61

4 0

3 years ago

HI I really need help with this its in the picture

Hitman42 [59]

<h3>Answer: 24a^4 + 36a^3 + 12a^2</h3>

Explanation:

The blue rectangle has area of 4a^2*6a^2 = 24a^4

The red rectangle has area 4a^2*9a = 36a^3

The green rectangle has area 4a^2*3 = 12a^2

The total area is 24a^4 + 36a^3 + 12a^2

7 0

3 years ago

Customers arrive at a grocery store at an average of 2.1 per minute. Assume that the number of arrivals in a minute follows the

Black_prince [1.1K]

Answer:

a) P(2)=0.270

b) P(X>3)=0.605

c) P=0.410

Step-by-step explanation:

We know that customers arrive at a grocery store at an average of 2.1 per minute. We use the Poisson distribution:

$\boxed{P(k)=\frac{\lambda^k \cdot e^{-\lambda}}{k!}}$

a) In this case: $\lambda=2.1$

$P(2)=\frac{2.1^2 \cdot e^{-2.1}}{2}\\\\P(2)=0.270$

Therefore, the probability is P(2)=0.270.

b) In this case: $\lambda=2\cdot 2.1=4.2$

$P(X>3)=1-P(X\leq 3)\\\\P(X>3)=1-\sum_{x=0}^3 \frac{4.2^x \cdot e^{-4.2}}{x!}\\\\P(X>3)=1-0.395\\\\P(X>3)=0.605$

Therefore, the probability is P(X>3)=0.605.

c) We know that two customers came in in the first minute. That is why we calculate the probability of at least 5 customers entering the other 2 minutes.

In this case: $\lambda=2\cdot 2.1=4.2$

$P(X\geq 5)=1-P(X$

Therefore, the probability is P=0.410.

4 0

3 years ago