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2 years ago

Find the volume of the cone of with a height of 6cm and a diameter of the base or 6cm

Mathematics

1 answer:

Ainat [17]2 years ago

7 0

Answer:

The volume of cone v= 113.04 cm³.

Step-by-step explanation:

Formula used to find volume of cone is:

$v= \pi * r^2 * \frac{h}{3}$

where r is the radius and h is the height of cone.

In the given question we are given:

height h= 6 cm

diameter d= 6 cm

We know radius r = d/2 = 6/2 = 3 cm

so, volume will be:

$v= \pi * 6^2 * \frac{3}{3}$

$v= \pi * 36$

$v=113.04$

So, the volume of cone v= 113.04 cm³ given height h= 6cm and radius r= 3cm

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A girl’s club held a fundraiser last year and raised $600 for the local soup kitchen. This year they raised $960. What is the pe

KatRina [158]

960-600 = $360

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3 years ago

4-2x=11 how do I solve

Bingel [31]

Hey there!☺

$Answer:\boxed{x=\frac{-7}{2}}$

$Explanation:$

$4-2x=11$

In our first step, we will simplify both sides of the equation:

$4+-2x=11\\-2x+4=11$

Now subtract 4 from both sides:

$-2x+4-4=11-4\\-2x=7$

In our last step, we will divide both sides by -2:

$\frac{-2x}{2}=\frac{7}{-2}\\ x=\frac{-7}{2}$

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2 years ago

If 7 people each eat 3/8 pound of potato salad, how much potato salad will be eaten in all?

Nikitich [7]

1 people eat 3/8 pound of potato salad lets reoresent it：
x=3/8
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7x=n
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2 years ago

How many two- fifths are in four-fifths

gulaghasi [49]

2 two-fifths are in four-fifths.

Hope this helps and have a great day!!!

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2 years ago

List all possible rational roots. Then use synthetic division to confirm which rational roots exist:

Kisachek [45]

Answer:

$\boxed{(1) \, x = \, \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10; (2) \, x = -2}$

Step-by-step explanation:

2x³+ 6x² - x - 10 = 0

(1) Possible roots

The Rational Roots Theorem states that, if a polynomial has any rational roots, they will have the form p/q, where p is a factor of the constant term and q is a factor of the leading coefficient.

$\text{Possible rational root} = \dfrac{ p }{ q } = \dfrac{\text{factor of constant term}}{\text{factor of leading coefficient}}$

In your function, the constant term is -10 and the leading coefficient is 2, so

$\text{Possible root} = \dfrac{\text{factor of 10}}{\text{factor of 2}}$

Factors of 10 = ±1, ±2, ±5, ±10

Factors of 2 = ±1, ±2

$\text{Possible roots are } \large \boxed{\mathbf{x = \pm \dfrac{1}{2}, \pm 1, \pm2, \pm \dfrac{5}{2}, \pm 5, \pm 10}}$

(2) Synthetic division

Rather than work through all 12 possibilities, I will do one that works.

$\begin{array}{r|rrrr}-2 & 2 & 6 & -1 & -10\\& & -4& -4 & 10\\& 2 & 2& -5 & 0\\\end{array}$

So, x = -2 is a root, and the quotient is 2x² + 2x - 5.

(3) Check for other rational roots

2x² + 2x - 5 = 0

D = b² - 4ac =2²- 4(2)(-5) = 4 + 40 = 44

√44 = 2√11, which is irrational.

Since irrational roots come in pairs, the cubic equation has two real, irrational roots and one rational root at x = -2.

6 0

3 years ago