2x-3y=13 equation (1)
x+2y=-4 equation (2)
multiply equation (2) by -2
-2x-4y=8 now we got equation (3)
Add equations(1) and (3) and combine like terms
2x-2x-3y-4y=13+8
-7y=21
y=-21/7= -3
substitute y with -3 in equation (2) and solve
<span>x+2(-3)=-4
</span>x-6=-4
x= -4+6
x=2
the solution for the system of equations is x=2, y= -3
Question #1:
a)
(4, 2)
Both of these are positive, and when x and y are both positive they're both in Quadrant 1.
b)
(x + 1, y - 5)
Add 1 to 'x', subtract 5 from 'y':
(4 + 1, 2 - 5)
(5, -3)
x is positive and y is negative, that means this will be in Quadrant 4.
c)
Reflection Across y-axis:
(-x, y)
Multiply -1 to 'x':
(5 * -1, -3)
(-5, -3)
Both of these are negative, if both x and y are negative it's located in Quadrant 3.
Question #2:
No, that can't tessellate a plane. We can't cover up space so there are no overlaps or gaps.
The answer is x=12 after I did the math that is my answer
Answer:
A you can check it by substituting values into x like 5 and 6 then compare the E(X) value
For normal distribution the mean is equal to the median.