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larisa [96]
3 years ago
8

Plz help me solve this and in the blue arrows you put inequality signs

Mathematics
1 answer:
klemol [59]3 years ago
8 0

Answer:

Step-by-step explanation:

(b/45) +7 > 5

(b/45) > -2

b > -90

Perimeter is 17 m ≥ 2* length 4.7 +2*widths

b. 9.4+2w ≤ 17

a. (2/7)n -10.6 < 12.4

(2/7)n <  12.4 +10.6

(2/7)n < 23

2n < 23*7

n < 161/2

n < 80.5

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195, 315, 540, 713, 1105 ¿Cuáles son divisibles entre 13?
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Step-by-step explanation:

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Naomi is reading a book that has 420 pages she reads 35 pages each day how many days will naomi need to finish this book
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3 years ago
Precalculus please help
JulijaS [17]

Answer:

amplitude = 2

period = 4

midline = y = -1

equation = either 2sin(\frac{pi}{2}x+\frac{pi}{2}  )-1 or 2sin(\frac{pi}{2}(x+1) )-1 depending on what format you're using

Step-by-step explanation:

the amplitude is the distance from the bottommost point to the topmost point

so if we use the points (0,1) and (2,-3), the min y value is -3 and the max y value is 1

so amplitude = ymax - ymin = 1 - - 3 = 4

amplitude = 4

the period is the distance it takes to complete one cycle

we have (0,1) and (4,1) which are two crest points

the distance between these is x2 - x1 = 4 - 0 = 4

period = 4

the midline is a horizontal line bisecting the sin line, which would be in the middle of its min and max y values

we already found that ymax = 1 and ymin = -3

so the midline would be y = (ymax + ymin) / 2 = (1 -3) /2 = -1

midline = y = -1

to find the sin equation, we will fill out the equation

asin(b(x-d))+c

a is the amplitude = 2

b = 2π/period = 2π/4 = π/2

c is the vertical shift. the midline of sine is originally at y = 0

since it is at y = -1 here, the vertical shift is -1 - 0 = -1

d is the horizontal shift. the middle of the upwards portion of the sine graph is originally at x = 0, but in the picture we see that it is at x = -1 so the shift is -1 - 0 = -1

a = 2, b = π/2, c = -1, d = -1

plug these values into the equation to get

asin(b(x-d))+c

2sin(π/2(x--1))+-1

=2sin(π/2(x+1))-1

=2sin(πx/2+π/2)-1

equation = either 2sin(\frac{pi}{2}x+\frac{pi}{2}  )-1 or 2sin(\frac{pi}{2}(x+1) )-1 depending on what format you're using

4 0
3 years ago
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