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Kipish [7]
3 years ago
14

A push or pull is called a force. Unbalanced forces can cause objects to move in many ways but not to move faster. B) move slowe

r. C) change direction. D) float in the air.
Physics
1 answer:
Allushta [10]3 years ago
6 0

Answer:

but not to

D). float in the air

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Which of the following has no energy?
Readme [11.4K]
The correct answer is D: which is none of the above.
Hint: a wreckling ball contains pontential energy that acts like a pendulum

a pot of water contains pontential thermal energy
4 0
4 years ago
Read 2 more answers
Suppose a family replaces ten 60-watt incandescent bulbs with ten 30-watt
mixer [17]

Initially there were 10 bulbs of 60 Watt power

So total power of all bulbs = 60 * 10 = 600 W

now each bulb used for 4 hours daily

so total energy consumed daily

E = p*t

E = 600*4 = 2400Wh

E = 2.4kWH

now we have total power consumed in 1 year

E = 365 * 2.4 = 876kWh

cost of electricity = 10 cents/ kWh

so total cost of energy for one year

P1  = 876*10 = 8760cents = 87.60

Now if all 60 Watt bulbs are replaced by 30 Watt bulbs

So total power of all bulbs = 30 * 10 = 300 W

now each bulb used for 4 hours daily

so total energy consumed daily

(The next steps are in the pic.)

5 0
3 years ago
This question is typical on some driver’s license exams: A car moving at 45 km/h skids 15 m with locked brakes. How far will the
sergiy2304 [10]

from kinematics equation if we know that final speed is ZERO and initial speed is given that due to constant deceleration the object will stop in some distance "d" and this distance can be calculated by kinematics

v_f^2 - v_i^2 = 2 a d

0 - v^2 = 2(a)d

here acceleration due to friction will be same at all different speed

so for 45 km/h speed the distance of stop is 15 m

while at other speed 112.5 km/h the distance will be unknown

now we will have

0 - 45^2 = 2(a)15

0 - 112.5^2 = 2(a)d

now divide above two equations

\frac{45^2}{112.5^2} = \frac{15}{d}

d = 93.75 m

So it will stop in distance 93.75 m

8 0
3 years ago
22. A 2.0 kg ball, traveling at 1.0 m/s, rolls off of a cliff of height 3.0 m. If the
RoseWind [281]

GOOD MORNING HAVE A NICE DAY

3 0
3 years ago
A moving walkway at an airport has a speed v1 and a length L. A woman stands on the walkway as it moves from one end to the othe
bearhunter [10]

Answer:

t=L/V_1

Explanation:

<u>solution:</u>

Let E be an observer, and B a second observer traveling with velocity V_{BE}  as measured by E. If E measures the velocity of an object A as V_{AE}  then B will measure A velocity as

V_{AB} = V_{AE} -  V_{BE}  

Applied here,

the walkway (W) and the man (M) are moving relative to Earth (E}, the velocity of the man relative to the moving walkway is

V_{MW} = V_{ME} -  V_{WE}  

V_1=V_{WE},

V_2=V_{MW}

The time required for the woman, traveling at constant speed V_1 relative to the ground, to travel distance L relative to the ground is :

t=L/V_1

 

3 0
4 years ago
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