1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alex777 [14]
3 years ago
5

A model rocket is launched at an angle of 70° above the x axis, with an initial velocity of 40m/s. How far horizontally will the

rocket travel?
A. 32.8m
B. 56.1m
C. 104.9m
D. 182.1m​
Physics
1 answer:
professor190 [17]3 years ago
5 0
I would say the answer should be B it will go higher then 40m but not as high as 104.9
You might be interested in
Usain Bolt's world-record 100 m sprint on August 16, 2009, has been analyzed in detail. At the start of the race, the 94.0 kg Bo
ZanzabumX [31]

a) 893 N

b) 8.5 m/s

c) 3816 W

d) 69780 J

e) 8030 W

Explanation:

a)

The net force acting on Bolt during the acceleration phase can be written using Newton's second law of motion:

F_{net}=ma

where

m is Bolt's mass

a is the acceleration

In the first 0.890 s of motion, we have

m = 94.0 kg (Bolt's mass)

a=9.50 m/s^2 (acceleration)

So, the net force is

F_{net}=(94.0)(9.50)=893 N

And according to Newton's third law of motion, this force is equivalent to the force exerted by Bolt on the ground (because they form an action-reaction pair).

b)

Since Bolt's motion is a uniformly accelerated motion, we can find his final speed by using the following suvat equation:

v=u+at

where

v is the  final speed

u is the initial speed

a is the acceleration

t is the time

In the first phase of Bolt's race we have:

u = 0 m/s (he starts from rest)

a=9.50 m/s^2 (acceleration)

t = 0.890 s (duration of the first phase)

Solving for v,

v=0+(9.50)(0.890)=8.5 m/s

c)

First of all, we can calculate the work done by Bolt to accelerate to a speed of

v = 8.5 m/s

According to the work-energy theorem, the work done is equal to the change in kinetic energy, so

W=K_f - K_i = \frac{1}{2}mv^2-0

where

m = 94.0 kg is Bolt's mass

v = 8.5 m/s is Bolt's final speed after the first phase

K_i = 0 J is the initial kinetic energy

So the work done is

W=\frac{1}{2}(94.0)(8.5)^2=3396 J

The power expended is given by

P=\frac{W}{t}

where

t = 0.890 s is the time elapsed

Substituting,

P=\frac{3396}{0.890}=3816 W

d)

First of all, we need to find what is the average force exerted by Bolt during the remaining 8.69 s of motion.

In the first 0.890 s, the force exerted was

F_1=893 N

We know that the average force for the whole race is

F_{avg}=820 N

Which can be rewritten as

F_{avg}=\frac{0.890 F_1 + 8.69 F_2}{0.890+8.69}

And solving for F_2, we find the average force exerted by Bolt on the ground during the second phase:

F_{avg}=\frac{0.890 F_1 + 8.69 F_2}{0.890+8.69}\\F_2=\frac{(0.890+8.69)F_{avg}-0.890F_1}{8.69}=812.5 N

The net force exerted by Bolt during the second phase can be written as

F_{net}=F_2-D (1)

where D is the air drag.

The net force can also be rewritten as

F_{net}=ma

where

a=\frac{v-u}{t} is the acceleration in the second phase, with

u = 8.5 m/s is the initial speed

v = 12.4 m/s is the final speed

t = 8.69 t is the time elapsed

Substituting,

a=\frac{12.4-8.5}{8.69}=0.45 m/s^2

So we can now find the average drag force from (1):

D=F_2-F_{net}=F_2-ma=812.5 - (94.0)(0.45)=770.2 N

So the increase in Bolt's internal energy is just equal to the work done by the drag force, so:

\Delta E=W=Ds

where

d is Bolt's displacement in the second part, which can be found by using suvat equation:

s=\frac{v^2-u^2}{2a}=\frac{12.4^2-8.5^2}{2(0.45)}=90.6 m

And so,

\Delta E=Ds=(770.2)(90.6)=69780 J

e)

The power that Bolt must expend just to voercome the drag force is given by

P=\frac{\Delta E}{t}

where

\Delta E is the increase in internal energy due to the air drag

t is the time elapsed

Here we have:

\Delta E=69780 J

t = 8.69 s is the time elapsed

Substituting,

P=\frac{69780}{8.69}=8030 W

And we see that it is about twice larger than the power calculated in part c.

3 0
3 years ago
A uniformly charged thin ring has radius 15.0 cm and total charge 20.0 nC . An electron is placed on the ring's axis a distance
Ivanshal [37]

Answer:

b) 1.67×10^7 m/s

Explanation:

The solution is attached in the attachment section

8 0
3 years ago
Which describes a feature of the physical changes of all substances?
JulijaS [17]

Answer:

A change in size, shape, or matter.

Explanation:

A physical change does not produce new substances. A physical change may only change the physical properties of a substance. a change in size, shape, or phase of matter.

8 0
2 years ago
An object of mass 5 m is lifted to a height of 5 h above the floor. What is the potential energy the object gained in this proce
Gekata [30.6K]

Answer:

Potential energy, E = 25 mgh

Explanation:

Given that,

Mass of the object, m = 5 m

It is lifted to a height of, h = 5 h

It is required to find the potential energy gained by the object. It is given by the product of object's mass, acceleration due to gravity and heigh above ground. It is given by :

E=m\times g\times h

E=5\ m\times g\times 5\ h

E = 25 mgh

So, the potential energy gained by the object is (25 mgh). Hence, this is the required solution.

7 0
3 years ago
An object is sitting on the floor. A 22.4 N force is pulling the object to the right and an 11 N force is pulling the object to
Nimfa-mama [501]

answer = 33.4 net force.

5 0
3 years ago
Other questions:
  • What gives an atom its charge?
    14·2 answers
  • In an electronic circuit, you need a capacitor to store 6.000e-9 J of energy. You have 1.50 volts available to charge it with. W
    8·1 answer
  • A bicycle tire is spinning clockwise at 3.40 rad/s. During a time period Δt = 2.50 s, the tire is stopped and spun in the opposi
    14·2 answers
  • predict the reading of the spring balance when the wooden block is pulled on the sandpaper. Explain your answer. ​
    8·1 answer
  • What is the equation for potential energy?
    12·2 answers
  • Mr. Phillips' car is parked on a steep hill with the brakes applied and the engine off. Because of the car's position, it has gr
    15·1 answer
  • QuestIuI
    10·1 answer
  • An object is traveling on a circle with a radius of 6 feet. If in 80 seconds a central angle of 9/4 radians is swept out, then f
    12·1 answer
  • Observe and compare the forces acting on the turtle and the cat.
    9·1 answer
  • A force of 15 newtons is used to push a box along the floor a distance of 3 meters. How much was done?
    12·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!