steve is happy today but he wasn't yesterday
1. non photorealistic rendering
2. siftables
3. spherical audio
4. blu ray
<h2>
Explanation:</h2>
Automation tools allow applications, businesses, teams or organizations to automate their processes which could be deployment, execution, testing, validation and so on. Automation tools help increase the speed at which processes are being handled with the main aim of reducing human intervention.
Linkedln automation tools are designed to help automate certain processes in Linkedln such as sending broadcast messages, connection requests, page following and other processes with less or no human or manual efforts. Some of these automation tools include;
i. <em>Sales navigator</em> for finding right prospects thereby helping to build and establish trusting relationships with these prospects.
ii. <em>Crystal </em>for providing insights and information about a specified Linkedln profile.
iii. <em>Dripify </em>used by managers<em> </em>for quick onboarding of new team members, assignment of roles and rights and even management of subscription plans.
The program is
num = int(input("Enter Numerator "))
den = int(input("Enter Denominator "))
print("quotient is ",str(num//den)," remainder is ", str(num%den))
<h3>
How to create a division sign in HTML?</h3>
To create a division sign ( ÷ ) in HTML you can use any of the following codes.
÷
÷
÷
<h3>
How to divide in computer programming?</h3>
Perl code
use strict;
my $first = 15;
my $second = 5;
my $answer = $first / $second;
print "You get $answer if you divide $first by $second";
When the script above is run, it displays "You get 3 if you divide 15 by 5" on the screen.
To learn more about programming, refer
https://brainly.ph/question/4743
#SPJ4
Answer:
See explaination for the code
Explanation:
def wordsOfFrequency(words, freq):
d = {}
res = []
for i in range(len(words)):
if(words[i].lower() in d):
d[words[i].lower()] = d[words[i].lower()] + 1
else:
d[words[i].lower()] = 1
for word in words:
if d[word.lower()]==freq:
res.append(word)
return res
Note:
First a dictionary is created to keep the count of the lowercase form of each word.
Then, using another for loop, each word count is matched with the freq, if it matches, the word is appended to the result list res.
Finally the res list is appended.
