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uysha [10]
3 years ago
6

2.05 times 10 to the power of 6 in standard notation

Mathematics
2 answers:
Natalka [10]3 years ago
7 0

Answer:

2050000

Step-by-step explanation:

10 to the power of 6= 1000000

2.05 x 1000000 = 2,050,000

Hence, 2.05 × 10^6 = 2050000

Hope this helps!

Please mark brainliest if you think I helped! Would really appreciate!

WARRIOR [948]3 years ago
4 0

2,050,000

Step-by-step explanation:

10 to the power of 6= 1000000.

2.05 x 1000000 = 2,050,000

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If a bloodstain has a length of 3.0cm and a width of 1.5cm what is the angle of impact?
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The angle of impact is 30°

<h3>What is the angle of impact?</h3>

In a bloodstain, the angle of impact can be used to determine the appearance of the resulting bloodstain if the bloodstain has a tail or pattern.

  • Bloodstain pattern analysis is the study of bloodstains at a scene of the crime in an attempt to reconstruct the events that resulted in the bloodshed.

Mathematically;

\mathbf{Angle  \ of \  impact = sin^{-1} (\dfrac{width \ stain}{length \ stain} )}

\mathbf{Angle  \ of \  impact = sin^{-1} (\dfrac{1.5}{3.0} )}

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Learn more about the angle of impact here:
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3 years ago
An e-mail filter is planned to separate valid e-mails from spam. The word free occurs in 60% of the spam messages and only 4% of
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Answer:

(a) 0.152

(b) 0.789

(c) 0.906

Step-by-step explanation:

Let's denote the events as follows:

<em>F</em> = The word free occurs in an email

<em>S</em> = The email is spam

<em>V</em> = The email is valid.

The information provided to us are:

  • The probability of the word free occurring in a spam message is,             P(F|S)=0.60
  • The probability of the word free occurring in a valid message is,             P(F|V)=0.04
  • The probability of spam messages is,

        P(S)=0.20

First let's compute the probability of valid messages:

P (V) = 1 - P(S)\\=1-0.20\\=0.80

(a)

To compute the probability of messages that contains the word free use the rule of total probability.

The rule of total probability is:

P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})

The probability that a message contains the word free is:

P(F)=P(F|S)P(S)+P(F|V)P(V)\\=(0.60*0.20)+(0.04*0.80)\\=0.152\\

The probability of a message containing the word free is 0.152

(b)

To compute the probability of messages that are spam given that they contain the word free use the Bayes' Theorem.

The Bayes' theorem is used to determine the probability of an event based on the fact that another event has already occurred. That is,

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

The probability that a message is spam provided that it contains free is:

P(S|F)=\frac{P(F|S)P(S)}{P(F)}\\=\frac{0.60*0.20}{0.152} \\=0.78947\\

The probability that a message is spam provided that it contains free is approximately 0.789.

(c)

To compute the probability of messages that are valid given that they do not contain the word free use the Bayes' Theorem. That is,

P(A|B)=\frac{P(B|A)P(A)}{P(B)}

The probability that a message is valid provided that it does not contain free is:

P(V|F^{c})=\frac{P(F^{c}|V)P(V)}{P(F^{c})} \\=\frac{(1-P(F|V))P(V)}{1-P(F)}\\=\frac{(1-0.04)*0.80}{1-0.152} \\=0.90566

The probability that a message is valid provided that it does not contain free is approximately 0.906.

4 0
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A movie theater uses a cone-shaped container to serve popcorn. The cone has a height of 12 inches and a volume of 16 π in2. What
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Volume can be defined as the <u><em>capacity of a given container or a certain object.</em></u>

The radius of the cone is 2 inches.

From the question, we are given the following parameters:

<em>The height of the cone = 12 inches</em>

<em>The volume of the cone =  16 π in³</em>

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