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vladimir2022 [97]
3 years ago
11

Which situation CANNOT be represented by this equation? 3x+4=19

Mathematics
2 answers:
Artist 52 [7]3 years ago
4 0

Answer:

Penny is selling candles for $4 each at a fund-raiser.

If she starts selling with $3 to help her make change, how many candles, x, will she have to sell to end up with $19?

8090 [49]3 years ago
3 0
I'm going with B Pennt is seling candles for 4$ each at a fund raiser if I'm right please give me branlest
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We can use the right outside diagonal of the empty Lacsap's triangle as the coefficients of a polynomial: $$t^3 + 6t^2 + 12t + 8
Vanyuwa [196]
The given equation with t -1 is:
(t – 1)^3 + 6 (t – 1)^2 + 12 (t – 1) + 8

Expand each term before combining for easier visualization:
(t – 1)^3 = t^3 – 3 t^2 + 3t – 1
6 (t – 1)^2 = 6 t^2 – 12 t + 6
12 (t – 1) = 12 t - 12

Then substitute and combine:
-> t^3 – 3 t^2 + 3t – 1 + 6 t^2 – 12 t + 6 + 12 t – 12 + 8

t^3 + 3 t^2 + 3 t + 1 (ANSWER)
7 0
3 years ago
2 women and 7 girls can do a peice of work in 4 days.4 women and 4 girls can do the same work in 3 days. How long would it take
svetlana [45]

Answer:

x: work a woman can do in 1 day

y: work a girl can do in 1  day

Then

2x + 7y =1/4

4x + 4y =1/3

4x + 14y =2/4 (1)

4x + 4y  =1/3 (2)

=> Let (1) - (2), 10y =2/4-1/3 <=>10y = 1/6 <=> y = 1/(6x10) = 1/60 (work)

=> From (2),4x = 1/3 - 4x1/60 => 4x = 16/60 => x = 4/60 (work)

=> 1 day, a woman and a girl can do: 1/60+4/60 = 5/60 =1/12 (work)

Then, the day required for a woman and a girl to complete work: 12 days

3 0
3 years ago
Find x. A. 11√6/2 B. 22 C. 33 D. 11√3/2
Phoenix [80]

Answer:

B

Step-by-step explanation:

using the tangent ratio on the triangle on the right and the exact value

tan60° = \sqrt{3} , then letting the altitude be h

tan60° = \frac{opposite}{adjacent} = \frac{11\sqrt{6} }{h}  = \sqrt{3} ( multiply both sides by h )

11\sqrt{6} = h × \sqrt{3} ( divide both sides by \sqrt{3} )

11\sqrt{2} = h

using the sine ratio in the triangle on the left and the exact value

sin45° = \frac{\sqrt{2} }{2} , then

sin45° = \frac{opposite}{hypotenuse} = \frac{h}{x} = \frac{11\sqrt{2} }{x} = \frac{\sqrt{2} }{2} ( cross- multiply )

\sqrt{2} × x = 22\sqrt{2} ( divide both sides by \sqrt{2} )

x = 22

6 0
1 year ago
Manuel has $600 in a savings account at the beginning of the summer. He wants to have at least $300 in the account at the end of
stiks02 [169]
The answer to this question is 600-28w > 300. This inequality can be described as $600 (money in the savings account) subtracted by $28w (withdrawal of $28 a week for food) should be greater than $300. It proves that the money will not drop below $300.
6 0
3 years ago
Read 2 more answers
H E L P<br> what is the slope??
earnstyle [38]
1/3 is the slope
X= 12-6=6
Y= 4-2=2
I got the slope 1/3 I used the points (6,2), (12.4)
7 0
3 years ago
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