Using the z-distribution, a sample size of 180 is needed for the estimate.
<h3>What is a z-distribution confidence interval?</h3>
The confidence interval is:
The margin of error is given by:
In which:
is the sample mean.
is the standard deviation for the population.
In this problem, we have a 98% confidence level, hence
, z is the value of Z that has a p-value of 
, so the critical value is z = 2.327.
The population standard deviation is of 
, and to find the sample size, we have to solve for n when M = 4.
Hence:
n = 179.03.
Rounding up, as a sample size of 179 would result in an error slightly above 4, a sample of 180 is needed.
More can be learned about the z-distribution at brainly.com/question/25890103
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To find the average, add all numbers together and divide by the amount of numbers there are
(85 + 92 + 84 + 85 + 96 + 95)/6 = 537/6 = 89.5
you're answer is 89.5 as average
hope this helps
Answer:
He's not right
Step-by-step explanation:
L = 4/6 = 2/3
K = 2/3
Answer:
135
Step-by-step explanation: 9x15=135
Answer:
12%
Step-by-step explanation:
Interés simple = Principal × Tasa × Tiempo
Tasa = Interés simple / Principal × Tiempo
Principal = 1700 soles
Tiempo = 1 año y 3 meses
12 meses = 1 año
3 meses = 3/12 = 1/4 = 0.25
Tiempo = 1.25 años
Tasa = 255 /1700 × 1.25
= 0.12
= 0.12 × 100
= 12%
