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3 years ago

Help!!(thank you so much)

Mathematics

1 answer:

mylen [45]3 years ago

8 0

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 10. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

Or just subtract

9.884 * 10^6 - 1.009 * 10^7=

− 2.05999999 × 10^5

Rounded up is:

− 2.06× 10^5

(❁´◡`❁)

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The angles of a triangle are described as follows: angle a is the largest angle; it measure is twice the measure of Angle b. The

nikklg [1K]

Answer:

Angle A = 102°

Angle B = 51°

Angle C = 27°

Step-by-step explanation:

angle A = 2b

angle B = b

angle C = 1/3 b + 10

Angle A + Angle B + Angle C = 180

2b + b + 1/3 b + 10 = 180

3 1/3 b + 10 = 180

10/3 b = 170

b = 51

a = 2b = 102

c = 1/3 b + 10 = 1/3 (51) + 10 = 17 + 10 = 27

4 0

3 years ago

Angles α and β are the two acute angles in a right triangle. Use the relationship between sine and cosine to find the value of β

Dimas [21]

Answer:

From given relation the value of β is 37.5°

Step-by-step explanation:

Given as :

α and β are two acute angles of right triangle

Acute angle have measure less than 90°

Now given as :

$sin(\frac{x}{2} + 2x)$ = $cos(2x +\frac{3x}{2})$

Or, $cos(90° - (\frac{x}{2}+2x))$ = $cos(2x +\frac{3x}{2})$

SO, $(90° - (\frac{x}{2}+2x))$ = $2x+\frac{3x}{2}$

Or, 90° = $2x+\frac{3x}{2}$ + $\frac{x}{2}+2x$

or, 90° = $\frac{4x}{2}$ + 4x

Or, 90° = $\frac{12x}{2}$

So, x = $\frac{90}{6}$ = 15°

∴ $sin(\frac{x}{2} + 2x)$ = $sin(\frac{15}{2} + 30)$

So, $sin(\frac{x}{2} + 2x)$ = sin $\frac{75}{2}$

∴ The value of Ф_1 = $\frac{75}{2}$ = 37.5°

Similarly $cos(2x +\frac{3x}{2})$ = $cos(30 +\frac{45}{2})$

So ,The value of Ф_2 = $\frac{105}{2}$ = 52.5°

∵ β α

So, As 37.5°52.5°

∴ β = 37.5°

Hence From given relation the value of β is 37.5° Answer

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3 years ago

What is this fraction as a decimal?

expeople1 [14]

14.4
hope this helps:)

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2 years ago

How can you use an algebraic expression on a coordinate plane?

nydimaria [60]

Putting it in the middle sorry if it isnt right i never was really good at these but i tried.

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