We are given 3 equations. Using these equations we can find f(h(2)).
h(x)=7x-5
h(2)=7(2)-5
h(2)=14-5
h(2)=9
f(x)=x^2-7
f(h(2))=(7x-5)^2-7
we know the answer for h(2) by now, so we can substitute for that.
f(9)=9^2-7
f(9)=81-7
f(9)=74
so f(h(2))=74
Sorry but grade math is this so I can have a better understanding
→ Solutions
⇒ Simplify <span><span><span>4<span>(<span>2a</span>)</span></span>+<span>7<span>(<span>−<span>4b</span></span>)</span></span></span>+<span><span>3c</span><span>(5)</span></span></span><span>⇒ </span><span><span><span><span><span>8a</span>+</span>−<span>28b</span></span>+<span>15<span>c
Answer
</span></span></span></span><span>⇒ </span><span>8a−28b</span><span>+</span><span>15c</span>
