Answer:
Probability, P(getting 2 toppings)= 0.1984
Step-by-step explanation:
Probability, P(1 toppings)= 1/7
Probability P of getting a particular topping is q = 1 - P = 1 - 1/7 = 6/7
Probability of( getting 2 toppings)= 7!/(2!5!)(1/7)^2 × (6/7)^5
P(getting 2 toopings)= (5040/240) × (0.020)× (0.4627)
P(getting 2 toppings)= 21 × 0.00948 = 0.1984
Answer:
is the resulting expression after grouping
Step-by-step explanation:
Given:
![-7x^3+21x^2+3x-9](https://tex.z-dn.net/?f=-7x%5E3%2B21x%5E2%2B3x-9)
Now taking common
from 1st 2 numbers and and 3 common from last we get
![-7x^2(x-3)+3(x-3)](https://tex.z-dn.net/?f=-7x%5E2%28x-3%29%2B3%28x-3%29)
Now taking x-3 common from both numbers we get
which is the final equation after grouping
Answer:-15x^3-x^2+8x+4
Sry if I am wrong
Step-by-step explanation:
Answer:
no false.
Step-by-step explanation: