Question

In a right triangle the length of a hypotenuse is c and the length of one leg is a, and the length of the other leg is b, what is the value of b, if c=2b, a=12?

Answer 1

To solve this problem you must apply the proccedure shown below:

1. You need to apply the Pythagorean Theorem:

$c^{2}=b^{2}+a^{2}$

Where c is the hypotenuse and the legs are a and b.

2. Now, you must substitute the values given in the problem above and solve for b:

$(2b)^{2}=b^{2}+12^{2}\\4b^{2}=b^{2}+144\\4b^{2}-b^{2}=144\\3b^{2}=144\\b=\sqrt{\frac{144}{3}}\\b=6.92$

Therefore, the answer is: The value of b is 6.92

Answer 2

Answer:

b= (square root of)48

Step-by-step explanation:

Use pythagoreon theorem,

and you get b^2=48