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3 years ago

What is the answer to -5/8x+1/4=1/8

Mathematics

2 answers:

igor_vitrenko [27]3 years ago

8 0

The answer to the question is x=2.6

natali 33 [55]3 years ago

3 0

Answer:B

Step-by-step explanation:

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Find x Round to the nearest tenth

nikdorinn [45]

Answer:

15.5

Step-by-step explanation:

So the formula here is the square of the tangent length is equal to the product of the exterior part of the secant line and total length of the secant.

So that means we have x^2=10(14+10).

After simplifying the right hand side we have the equation is x^2=10(24) or x^2=240.

To get rid of the square on the x, we square root both sides.

x=sqrt(240)

x=15.49193338

To the nearest tenths, the answer is x=15.5

So 15.5 inches is the length of x.

3 0

3 years ago

A baseball player lost 20% of the games he pitched. If he pitched 40 ball games how many games dis he win?

emmainna [20.7K]

Answer:

Step-by-step explanation:

When you multiply 40 by 20% or 0.20, the product will be the amount of games he lost. When you subtract 40-8 you get how many games he won.

5 0

3 years ago

Given a joint PDF, f subscript X Y end subscript (x comma y )equals c x y comma space 0 less than y less than x less than 4, (1)

ioda

(1) Looks like the joint density is

$f_{X,Y}(x,y)=\begin{cases}cxy&\text{for }0$

In order for this to be a proper density function, integrating it over its support should evaluate to 1. The support is a triangle with vertices at (0, 0), (4, 0), and (4, 4) (see attached shaded region), so the integral is

$\displaystyle\int_0^4\int_y^4 cxy\,\mathrm dx\,\mathrm dy=\int_0^4\frac{cy}2(4^2-y^2)=32c=1$

$\implies\boxed{c=\dfrac1{32}}$

(2) The region in which X > 2 and Y < 1 corresponds to a 2x1 rectangle (see second attached shaded region), so the desired probability is

$P(X>2,Y$

(3) Are you supposed to find the marginal density of X, or the conditional density of X given Y?

In the first case, you simply integrate the joint density with respect to y:

$f_X(x)=\displaystyle\int_{-\infty}^\infty f_{X,Y}(x,y)\,\mathrm dy=\int_0^x\frac{xy}{32}\,\mathrm dy=\begin{cases}\frac{x^3}{64}&\text{for }0$

In the second case, we instead first find the marginal density of Y:

$f_Y(y)=\displaystyle\int_y^4\frac{xy}{32}\,\mathrm dx=\begin{cases}\frac{16y-y^3}{64}&\text{for }0$

Then use the marginal density to compute the conditional density of X given Y:

$f_{X\mid Y}(x\mid y)=\dfrac{f_{X,Y}(x,y)}{f_Y(y)}=\begin{cases}\frac{2xy}{16y-y^3}&\text{for }y$

6 0

3 years ago

Frederico's checking account balance is -$15, and Neela's checking account balance is -$285. How many times the balance of Frede

olya-2409 [2.1K]

Answer:

Step-by-step explanation:

the answer is 2 because I need points for my brainly so I can get a 100 on this assignment

5 0

3 years ago

PLEASEEE HELP ILL GIVE BRAINLIEST

morpeh [17]

I'm pretty sure the answer would be false. It's should be -7 because it's counting down 1 2 3.

5 0

3 years ago

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