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LenKa [72]
4 years ago
12

A number t decreased by 2 is at least 7

Mathematics
1 answer:
9966 [12]4 years ago
6 0
Answer:
t - 2 ≥ 7; t ≥ 9

Explanation:
“a number t” = t
“decreased by 2” = - 2
“Is at least 7” = ≥ 7
So, t - 2 ≥ 7

To solve for t - 2 ≥ 7, add 2 to both sides of the equation

t - 2 ≥ 7
t - 2 + 2 ≥ 7 + 2
t ≥ 9

So, t ≥ 9
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When completing the square on the equation c 2 11c = 12, the resulting equation is:
QveST [7]
C^2 + 11c = 12

c^2 + 2[11/2] c = 12

[c + 11/2] ^2 - [11/2]^2 = 12

[c +11/2]^2 = 12 +[11/2]^2

[c +11/2]^2 = 12 + 121/4

[c +11/2]^2 =[48+121]/4

[c +11/2]^2 = 169/4  ----> This is the resulting equation

Solving it you get:

c + 11/2 = +/- √(169/4)

c + 11/2 = +/- 13/2

c = 13/2 - 11/2 =2/2 = 1 and

c = -13/2 - 11/2 = - 24/2 = -12

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3 years ago
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Answer:

1.  16

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Step-by-step explanation:

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Canceling the x-1  in the top and bottom

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Let x=1

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First factor the expression

    lim x→0 (x-4) (x-2) /(x-2)        

Canceling the x-2  in the top and bottom

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Let x=0

lim x→0   (0-4) = -4

Filling in the table

x     -.1      -.01       -.001     .001     .01     .1

f(x) -4.1  -4.01    -4.001   -3.999   -3.99  -3.9

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3 years ago
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Answer:

For number 5 . a= 3 and b = -1

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