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Rashid [163]
3 years ago
12

A 4:1 scale drawing of a bearing is shown on an A-size print. Using a ruler, you measure the inside diameter of the part on the

paper and you get 1.50 inches. What is the actual part size in inches? A. 6.0 B. 1.5 C.4.0 D 375
Mathematics
1 answer:
Pani-rosa [81]3 years ago
4 0

Answer:

A. 6.0

Step-by-step explanation:

We have been given that the the inside diameter of the part on the paper is 1.50 inches.

We have been given that scale is 4:1 for actual size to drawing side.

\text{Scale}=\frac{\text{Actual size}}{\text{Map size}}=\frac{4}{1}

Upon substituting 1.50 in our given proportion, we will get:

\frac{\text{Actual size}}{1.50\text{ inches}}=\frac{4}{1}

\frac{\text{Actual size}}{1.50\text{inches}}\times 1.50\text{ inches}=\frac{4}{1}\times 1.50\text{ inches}

\text{Actual size}=4\times 1.50\text{ inches}

\text{Actual size}=6.0\text{ inches}

Therefore, the actual size is 6.0 inches and option A is the correct choice.

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