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Rashid [163]
3 years ago
12

A 4:1 scale drawing of a bearing is shown on an A-size print. Using a ruler, you measure the inside diameter of the part on the

paper and you get 1.50 inches. What is the actual part size in inches? A. 6.0 B. 1.5 C.4.0 D 375
Mathematics
1 answer:
Pani-rosa [81]3 years ago
4 0

Answer:

A. 6.0

Step-by-step explanation:

We have been given that the the inside diameter of the part on the paper is 1.50 inches.

We have been given that scale is 4:1 for actual size to drawing side.

\text{Scale}=\frac{\text{Actual size}}{\text{Map size}}=\frac{4}{1}

Upon substituting 1.50 in our given proportion, we will get:

\frac{\text{Actual size}}{1.50\text{ inches}}=\frac{4}{1}

\frac{\text{Actual size}}{1.50\text{inches}}\times 1.50\text{ inches}=\frac{4}{1}\times 1.50\text{ inches}

\text{Actual size}=4\times 1.50\text{ inches}

\text{Actual size}=6.0\text{ inches}

Therefore, the actual size is 6.0 inches and option A is the correct choice.

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e^(ln x) is just plain x

Step-by-step explanation:

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P is the principal amount

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r is the rate of interest.

Here, we are given that:

Amount, A = $15000

Rate of interest = 13 % compounded quarterly i.e. 4 times every year

Number of times, interest is compounded each year, n = 4

Time, t = 4 years.

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Putting all the given values in the formula to find P.

15000 = P(1 + \frac{13}{400})^{4\times 4}\\\Rightarrow 15000 = P(1 + 0.0325)^{16}\\\Rightarrow 15000 = P(1.0325)^{16} \\\Rightarrow 15000 = P \times 1.66817253\\\Rightarrow P = \dfrac{15000}{1.66817253}\\\Rightarrow P \approx \$8991.88

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Now, we take the square root to both sides:

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h=22.361km

Therefore, the length of the hypotenuse is 22.361 kilometers.

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