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N76 [4]
3 years ago
10

The GT brewery has hired you as an analyst to understand its market position. It is particularly concerned about its major compe

titor, the ML Brewery, and which brewery has the ‘lead’ market share. Recent history has suggested that which brewery has the ‘lead market share’ can be modeled as a Markov Chain using three states: GT, ML, and Other Company (OC). Data on the lead market share is taken monthly and you have constructed the following one-step transition probability matrix from past data:
GT ML OC
GT 0.75 0.15 0.10
ML 0.30 0.60 0.10
OC 0.20 0.10 0.70

a. The current state of the lead market share in November is GT·The GT Brewery is considering launching a new brand in March only if it has the lead market share in February. Determine the probability that GT Brewery will launch this new brand. Please show any equations or matrices used to calculate this probability and briefly explain how you obtained your answer.
b. Provide the steady-state equations and calculate the steady-state probabilities for the Markov Chain.

Mathematics
1 answer:
Stolb23 [73]3 years ago
8 0

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.  

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(2,4)   (4,8)

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Christian is planning a vacation and finds an airplane ticket that cost 180$. He found a promo code offering 17% off. Write a si
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Answer:

83/100 x 180

Step-by-step explanation:

We have to find the cost of the ticket after the discount.

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83% of the total percentage of the original price that he needs to pay.

So we do:

83/100 x 180

So, this would be the expression.

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3 years ago
Demand for Tablet Computers The quantity demanded per month, x, of a certain make of tablet computer is related to the average u
soldier1979 [14.2K]

x = f ( p ) = \frac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } } \\\\ \qquad { p ( t ) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \quad ( 0 \leq t \leq 60 ) }

Answer:

12.0 tablet computers/month

Step-by-step explanation:

The average price of the tablet 25 months from now will be:

p ( 25) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { 25 } } + 200 \\= \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \times 5 } + 200\\\\=\dfrac { 400 } { 1 + \dfrac { 5 } { 8 } } + 200\\p(25)=\dfrac { 5800 } {13}

Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}

\dfrac{dx}{dp}= \dfrac{d}{dp}\left[{ \dfrac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } }\right] =-\dfrac{100}{9}p(810,000-p^2)^{-1/2}

\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}

Therefore:

\dfrac{dx}{dt}= \left[-\dfrac{100}{9}p(810,000-p^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}\right]

Recall that at t=25, p(25)=\dfrac { 5800 } {13} \approx 446.15

Therefore:

\dfrac{dx}{dt}(25)= \left[-\dfrac{100}{9}\times 446.15(810,000-446.15^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt {25} \right]^{-2}25^{-1/2}\right]\\=12.009

The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

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3 years ago
Find the median of the following set of data 12,20,1,20,8
Alenkasestr [34]

Answer:

ok, i hate questions like these because i don't want to answer them

Step-by-step explanation:

6 0
3 years ago
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