The GT brewery has hired you as an analyst to understand its market position. It is particularly concerned about its major compe
titor, the ML Brewery, and which brewery has the ‘lead’ market share. Recent history has suggested that which brewery has the ‘lead market share’ can be modeled as a Markov Chain using three states: GT, ML, and Other Company (OC). Data on the lead market share is taken monthly and you have constructed the following one-step transition probability matrix from past data:
GT ML OC
GT 0.75 0.15 0.10
ML 0.30 0.60 0.10
OC 0.20 0.10 0.70
a. The current state of the lead market share in November is GT·The GT Brewery is considering launching a new brand in March only if it has the lead market share in February. Determine the probability that GT Brewery will launch this new brand. Please show any equations or matrices used to calculate this probability and briefly explain how you obtained your answer.
b. Provide the steady-state equations and calculate the steady-state probabilities for the Markov Chain.
GT ML OC
GT 0.75 0.15 0.10
ML 0.30 0.60 0.10
OC 0.20 0.10 0.70
a. The current state of the lead market share in November is GT·The GT Brewery is considering launching a new brand in March only if it has the lead market share in February. Determine the probability that GT Brewery will launch this new brand. Please show any equations or matrices used to calculate this probability and briefly explain how you obtained your answer.
b. Provide the steady-state equations and calculate the steady-state probabilities for the Markov Chain.
1 answer:
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Answer:
(a) even function
(b) odd function
Step-by-step explanation:
From the given information;
Any function x(t) can be said to be the sum of even and odd functions.
i.e.
where;
x(t) is a real function.
For a real and even function, the Fourier transform is also real and even.
Also, the Fourier Transform of a real and odd function is imaginary and odd.
The behavior of X(f) largely depends on the behavior of x(t).
If x(t) is real and even, then x(f) is real and even valued function
Thus, the real part of X(f) is an even function.
If x(t) is real and odd, then x(f) is imaginary and odd valued function
Thus, the imaginary part of X(f) is an odd function.