Answer:
The 99% confidence interval for the population mean is 22.96 to 26.64
Step-by-step explanation:
Consider the provided information,
A sample of 49 customers. Assume a population standard deviation of $5. If the sample mean is $24.80,
The confidence interval if 99%.
Thus, 1-α=0.99
α=0.01
Now we need to determine 
Now by using z score table we find that 
The boundaries of the confidence interval are:

Hence, the 99% confidence interval for the population mean is 22.96 to 26.64
I believe it's b , hopefully this helps
what is the approximate square root to 115
10.7
Step-by-step explanation:
this is the ans
Answer:
11/5
Step-by-step explanation:
You multiply 2 by 5 to give us 10. Add 1 the numerator of the equation giving us 11. Then we say 11/5