By definition, the perimeter of the triangle is the sum of its sides.
We must then use the formula of distance between points:

We now look for the longitus for each of the sides:
For L1:

For L2:

For L3:
Then, the perimeter is given by:
P = L1 + L2 + L3
Substituting values we have:
Answer:
the perimeter of triangle ABC is:
none of the above.
ANSWER If you solve for x you get -4/3 y+5/6 If you solve for y you get -3/4x +5/8.
Step-by-step explanation
and then the second answer is
If you solve for x you get-4/3y +-1/2
If you solve for y you get -3/4x +-1/2
Answer:
C. Triangle BAC is congruent to triangle FDE by AAS
Step-by-step explanation:
BAC names the vertices in the order longest-side, shortest-side. That same order is FDE in the other triangle, eliminating choiced B and D. The triangles are not right triangles, eliminating choice A.
The only viable answer choice is C.
No specific sides are shown as being congruent, but two angles are, so we could claim congruence by ASA or AAS. Answer choice C uses the latter.
Step-by-step explanation:
Let the 1st number be x
2nd number = x + 2
3rd number = x + 4
4th number = x + 6
5th number = x + 8
x + x + 2 + x + 4 + x + 6 + x + 8 = 20
5x + 20 = 20
5x = 20 - 20
5x = 0
x = 0 ÷ 5
x = 0
The 5 consecutive integers are
0, 2, 4, 6, 8