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3 years ago

Please help urgent ❤️❤️❤️❤️

Mathematics

1 answer:

Lorico [155]3 years ago

5 0

Answer:

B,Friday

Step-by-step explanation:

4 to 9 is 5 hours,the total hours for the week is 32.5 hours

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Question 1. Solve using linear combination

Natali5045456 [20]

1) 4d = 24
d = 6
answer d

2) 4d = 12
d = 3
answer c

3) y = 0
ordered pair: (-5 , 0)

Hope this helps!

4 0

3 years ago

What are the coordinates of the circumcenter of this triangle?

balu736 [363]

Answer:

(0.5, 0.5)

Step-by-step explanation:

draw lines in the middle of each side and the points line up in one spot

5 0

2 years ago

Read 2 more answers

Can u answer this please?

denpristay [2]

2. 2 increasing
3. Y=-x +9 decreasing
4. 2 increasing
5. 6 increasing
6. Y=-3x+1 decreasing

5 0

2 years ago

Slove the following:

Aleksandr [31]

Answer:

let required no be x

$\frac{1}{7} = \frac{x}{42}$

by doing crisscrossed multiplication

$42 \times 1 = 7 \times x$

42=7x

dividing both side by 7

$\frac{42}{7} = 7x \div 7$

6=x

therefore x=6

therefore value of remaining no.is 6

7 0

2 years ago

Read 2 more answers

What’s is the answer

kvasek [131]

When you are multiplying an exponent directly into a number/variable with an exponent, you multiply the exponents together.

For example:

$(x^{2} )^{3} = x^6$

$(x^{3} )^5=x^{15}$

When you are multiplying a variable with an exponent by another variable with an exponent, you add the exponents together.

For example:

$(x^{2} )(x^{3})=x^{5}$

$(x^{1} )(x^{2})=x^{3}$

$(\frac{(x^{-3})(y^{2})}{(x^{4})(y^{6})} )^{3}=\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}$

You multiply 3 into each exponent in the numerator and the denominator

$\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}= \frac{y^{6}}{(x^{9})(x^{12})(y^{18})}$

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive.

$\frac{y^{6}}{(x^{21})(y^{18})} = \frac{1}{(x^{21})(y^{12})}$

When you have something like this:

$\frac{x^{2}}{x^5}$

You subtract the exponents together, so:

$\frac{x^2}{x^5} = x^{2-5} = x^{-3} = \frac{1}{x^3}$

Your answer is the second option

3 0

3 years ago