Question

1. Isosceles Triangle The two equal sides of an isosceles triangle are each 42

Answer 1

Answer:

1. H = 29 cm

2. θ = 44°

Step-by-step explanation:

1. We can find the height of the triangle by considering the isosceles triangle as two right triangles. The height can be found by using Pitagoras:

$L^{2} = H^{2} + B^{2}$

Where:

L: is the sides of the isosceles triangle = 42 cm

B: is the base = 30 cm

H: is the height =?

Then, the height is:

$H = \sqrt{L^{2} - B^{2}} = \sqrt{(42 cm)^{2} - (30 cm)^{2}} = 29.4 cm = 29 cm$

2. The two equal angles (θ) can be found using the following trigonometric identity:          

$cos(\theta) = \frac{B}{L}$

$\theta = cos^{-1}(\frac{30 cm}{42 cm}) = 44.4^{\circ} = 44^{\circ}$

Hence, the two equal angles are 44°.

I hope it helps you!