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3 years ago

-2(-6x+3u-1) use the distributive property to remove parentheses

Mathematics

2 answers:

kvv77 [185]3 years ago

8 0

Simplify the expression.

3uv^2-6v^2x-v^2

Nikitich [7]3 years ago

4 0

the answer is 12x-6u+2 hope this helps

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The formula 2y = 3x + 6 is used in chemistry. How can this formula be solved for Y?

lord [1]

$2y = 3x + 6\\y = \frac{3}{2}x + \frac{6}{2} = \frac{3}{2}x + 3$

8 0

3 years ago

#9) PLEASE HELP WITH QUESTION! MARKING BRAINLIEST +POINTS

umka2103 [35]

D) Vertices: (1, -1), (-11, -1); Foci: (-15, -1), (5, -1)

4 0

3 years ago

A wire b units long is cut into two pieces. One piece is bent into an equilateral triangle and the other is bent into a circle.

mezya [45]

1. Divide wire b in parts x and b-x.

2. Bend the b-x piece to form a triangle with side (b-x)/3

There are many ways to find the area of the equilateral triangle. One is by the formula A= $\frac{1}{2}sin60^{o}side*side= \frac{1}{2} \frac{ \sqrt{3} }{2} (\frac{b-x}{3}) ^{2}= \frac{ \sqrt{3} }{36}(b-x)^{2}$
A= $\frac{ \sqrt{3} }{36}(b-x)^{2}=\frac{ \sqrt{3} }{36}( b^{2}-2bx+ x^{2} )=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}$

Another way is apply the formula A=1/2*base*altitude,
where the altitude can be found by applying the pythagorean theorem on the triangle with hypothenuse (b-x)/3 and side (b-x)/6

3. Let x be the circumference of the circle.

$2 \pi r=x$

so $r= \frac{x}{2 \pi }$

Area of circle = $\pi r^{2}= \pi ( \frac{x}{2 \pi } )^{2} = \frac{ \pi }{ 4 \pi ^{2} }* x^{2} = \frac{1}{4 \pi } x^{2}$

4. Let f(x)= $\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}+\frac{1}{4 \pi } x^{2}$

be the function of the sum of the areas of the triangle and circle.

5. f(x) is a minimum means f'(x)=0

f'(x)= $\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x$ =0

$\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0$

$(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) x=\frac{ \sqrt{3} }{18}b$

$x= \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

6. So one part is $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$ and the other part is b- $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

4 0

4 years ago

Read 2 more answers

A farmer has both pigs and chickens on his farm there are 78 fee and 27 heads how many pigs and how many chickens are there

Andre45 [30]

Assuming health non-mutated animals:
$Feet = 4*Pigs + 2*Chickens$
$Heads = Pigs + Chickens$

By back substitution:
$78 = 4*(27-Chickens) + 2*Chickens$
$78 = 108 -2*Chickens$
$-30 = -2*Chickens$
$Chickens= 15$

Then:
$27 = Pigs + 15$
$Pigs = 12$

To check:
$Feet = 4*Pigs + 2*Chickens$
$78 = 4*12 + 2*15$
$78 = 48 + 30$
$78 = 78$ CHECKS

6 0

3 years ago

What integer and -3 have a quotient 9?

Juli2301 [7.4K]

-3 is your the answer a negitive times a negitive is a positive
happy to help

6 0

3 years ago