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ExtremeBDS [4]
3 years ago
14

What is Number 13 plss I need answer ASAP

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
3 0

Answer:

Step-by-step explanation:

As you can see, she bought 8 muffins and 2 of them were apple, and the other 2 were banana.

( The rest were blueberry )

Since her family ate the APPLE and BANANA muffins, it's asking you to find the FRACTION of the muffins they ate. So 4 banana and apple muffins outta 3 varieties ( Total 8 muffins )  and 4 blueberry left.

So it's like 4 outta 8

idk I think im wrong :,U

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I'm having trouble with #2. I've got it down to the part where it would be the integral of 5cos^3(pheta)/sin(pheta). I'm not sur
Butoxors [25]
\displaystyle\int\frac{\sqrt{25-x^2}}x\,\mathrm dx

Setting x=5\sin\theta, you have \mathrm dx=5\cos\theta\,\mathrm d\theta. Then the integral becomes

\displaystyle\int\frac{\sqrt{25-(5\sin\theta)^2}}{5\sin\theta}5\cos\theta\,\mathrm d\theta
\displaystyle\int\sqrt{25-25\sin^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta
\displaystyle5\int\sqrt{1-\sin^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta
\displaystyle5\int\sqrt{\cos^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta

Now, \sqrt{x^2}=|x| in general. But since we want our substitution x=5\sin\theta to be invertible, we are tacitly assuming that we're working over a restricted domain. In particular, this means \theta=\sin^{-1}\dfrac x5, which implies that \left|\dfrac x5\right|\le1, or equivalently that |\theta|\le\dfrac\pi2. Over this domain, \cos\theta\ge0, so \sqrt{\cos^2\theta}=|\cos\theta|=\cos\theta.

Long story short, this allows us to go from

\displaystyle5\int\sqrt{\cos^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta

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\displaystyle5\int\cos\theta\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta
\displaystyle5\int\dfrac{\cos^2\theta}{\sin\theta}\,\mathrm d\theta

Computing the remaining integral isn't difficult. Expand the numerator with the Pythagorean identity to get

\dfrac{\cos^2\theta}{\sin\theta}=\dfrac{1-\sin^2\theta}{\sin\theta}=\csc\theta-\sin\theta

Then integrate term-by-term to get

\displaystyle5\left(\int\csc\theta\,\mathrm d\theta-\int\sin\theta\,\mathrm d\theta\right)
=-5\ln|\csc\theta+\cot\theta|+\cos\theta+C

Now undo the substitution to get the antiderivative back in terms of x.

=-5\ln\left|\csc\left(\sin^{-1}\dfrac x5\right)+\cot\left(\sin^{-1}\dfrac x5\right)\right|+\cos\left(\sin^{-1}\dfrac x5\right)+C

and using basic trigonometric properties (e.g. Pythagorean theorem) this reduces to

=-5\ln\left|\dfrac{5+\sqrt{25-x^2}}x\right|+\sqrt{25-x^2}+C
4 0
2 years ago
Read 2 more answers
Given an integer, how do you find it's opposite?
Dimas [21]
Given an integer, how do u find its opposite....

change the sign

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6 0
3 years ago
1) 3(3x - 4) = -2(1 – 4x)
Yanka [14]
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3
(
3
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−
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=
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(
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3
(
3
x
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4
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=
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2
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−
4
x
)
(
3
)
(
3
x
)
+
(
3
)
(
−
4
)
=
(
−
2
)
(
1
)
+
(
−
2
)
(
−
4
x
)
(Distribute)
9
x
+
−
12
=
−
2
+
8
x
9
x
−
12
=
8
x
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2
Step 2: Subtract 8x from both sides.
9
x
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12
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8
x
=
8
x
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2
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8
x
x
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12
=
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2
Step 3: Add 12 to both sides.
x
−
12
+
12
=
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2
+
12
x
=
10
6 0
3 years ago
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80

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because 8 is in tens place

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2 years ago
Cuanto es 90 x 90 entre 50?
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