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3 years ago

PLEASE HELP ASAP!!! 70 POINTS AND BRAINLIEST!!!

Mathematics

2 answers:

Lelu [443]3 years ago

5 0

You should use this app called desmos to solve this but its the last option

kumpel [21]3 years ago

4 0

Answer:

y =x+3

Step-by-step explanation:

We need to find the slope

Find 2 points

(-3,0) and (0,3)

Slope = (y2-y1)/(x2-x1)

= (3-0)/ (0--3)

= (3-0)/ (0+3)

=3/3

We know the y intercept ( where it crosses the y axis) is at 3

We can write the equation in the form y= mx+b

y = 1x+3

y =x+3

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2 years ago

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Plz help I am timed I WILL GIVE BRAINLIEST

EleoNora [17]

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Step-by-step explanation:

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3 years ago

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3 years ago

Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re

fiasKO [112]

Answer: $R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}$

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts $38^{\circ}$ angle to each other

The resultant of the two forces is given by

$\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}$

Insert the values

$\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb$

Resultant makes an angle of

$\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}$