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guajiro [1.7K]
3 years ago
12

32% of 89.9 answer????​

Mathematics
1 answer:
Annette [7]3 years ago
5 0

Answer:

28.768

The drawing will help

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What is the equation of the line, in slope-intercept form, that passes through (3, -1) and (-1,5)?
romanna [79]
m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{5 - (-1)}{-1 - 3} = \frac{5 + 1}{-4} = \frac{6}{-4} = \frac{3}{-2} = -1\frac{1}{2}
  y - y₁ = m(x - x₁)
y - (-1) = -1¹/₂(x - 3)
  y + 1 = -1¹/₂(x) + 1¹/₂(3)
  y + 1 = -1¹/₂x + 4¹/₂
      - 1              - 1
         y = -1¹/₂x + 3¹/₂

  4x + y - 2 = 0
            + 2 + 2
       4x + y = 2
4x - 4x + y = -4x + 2
               y = -4x + 2
         y - y₁ = m(x - x₁)
      y - (-3) = -4(x - 4)
         y + 3 = -4(x) + 4(4)
         y + 3 = -4x + 16
             - 3            - 3
               y = -4x + 13

  2x - 3y - 5 = 0
             + 5 + 5
2x - 2x - 3y = -2x + 5
             -3y = -2x + 5
              -3         -3
                y = ²/₃x - 1²/₃
       y - (-3) = -1¹/₂(x - 4)
          y + 3 = -1¹/₂(x) + 1¹/₂(4)
          y + 3 = -1¹/₂x + 6
              - 3              - 3
                y = -1¹/₂x + 3

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The answer would correctly be letter B
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The light from a lamp creates a shadow on a wall with a hyperbolic border. Find the equation of the border if the distance betwe
dolphi86 [110]

This question is incomplete, the complete question is;

The light from a lamp creates a shadow on a wall with a hyperbolic border. Find the equation of the border if the distance between the vertices is 18 inches and the foci are 4 inches from the vertices. Assume the center of the hyperbola is at the origin.

Answer:

the equation of the border is x²/81 - y²/88 = 1

Step-by-step explanation:

Given the data in the question;

distance between vertices = 2a = 18 in

so

a = 18/2 = 9 in

distance of foci from vertices = 4 in

hence distance between two foci = 2c = 18 + 4 + 4 =  26

so

c = 26/2 = 13 in

Now, from Pythagorean theorem

b = √( c² - a² )

we substitute

b = √( (13)² - (9)² ) = √( 169 - 81 ) = √88

we know center is at the origin, so

( h, k ) = ( 0, 0 )

h = 0

k = 0

Using equation of hyperbola

[ ( x-h )² / a² ] - [ ( y - k )² / b² = 1

we substitute

[ ( x-0 )² / 9² ] - [ ( y - 0 )² / (√88)² ] = 1

x²/81 - y²/88 = 1

Therefore, the equation of the border is x²/81 - y²/88 = 1

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Write the polynomial as a product of a difference and a sum: b^2-4/9
Alenkinab [10]

Answer:

\sf \huge \boxed{ \boxed{(b  +   \frac{2}{3} )(b -  \frac{2}{3} )}}

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • algebra
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<h3>tips and formulas:</h3>
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<h3>let's solve:</h3>
  1. \sf \: rewrite : \\ (  {b})^{2}  - (  \frac{2}{3}  {)}^{2}
  2. \sf use \: the \: formula :  \\ (b  +   \frac{2}{3} )(b -  \frac{2}{3} )

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