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Veseljchak [2.6K]
3 years ago
10

Can you please help me out this is DUE IN 5 MINUTES please.

Mathematics
1 answer:
Rina8888 [55]3 years ago
5 0

Answer

You flip it, so

Step-by-step explanation:

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Every quadrilateral with opposite angles supplementary can be inscribed in a circle.TrueFalseIf a triangle is inscribed in a cir
solniwko [45]

Explanation

The Inscribed Quadrilateral Theorem states that a quadrilateral can be inscribed in a circle if and only if the opposite angles of the quadrilateral are supplementary

Answer 1: True

Also, Given a triangle, the circumscribed circle is the circle that passes through all three vertices of the triangle. The center of the circumscribed circle is the circumcenter of the triangle, the point where the perpendicular bisectors of the sides meet.

Answer 2: True

7 0
1 year ago
What is the following sum in simplest form?
elena55 [62]

Answer:

C.  9√2.

Step-by-step explanation:

√8 + 3 √2+ √ 32

= √4 *√2 + 3√2 +  √16*√2

= 2√2 + 3√2 + 4√2

= 9√2.

8 0
3 years ago
Find the perimeter of triangle PQR. Round your answer to the nearest tenth.
BabaBlast [244]
We are given the coordinate of the 3 vertices. From these coordinates we can find the length of the sides using the distance formula and the sum of all the sides will be equal to the perimeter of the triangle.

Side PQ = \sqrt{ (6-(-2))^{2}+  (1-1)^{2} }=8

Side QR = \sqrt{ (4-6)^{2}+ (-3-1)^{2} }=4.5

Side RP = \sqrt{ (2-(-4))^{2}+ (-3-1)^{2} }=7.2

So, the perimeter of the triangle will be 8 + 4.5 + 7.2 = 19.7 

You probably misplaced the digits in option A. The correct answer is 19.7 units.
3 0
3 years ago
Why can't the stork deliver heavy babies
natulia [17]
Cause its a bird and they eat the bigger ones

5 0
3 years ago
WILL GIVE ALL POiNTS IF ANSWERED CORRECTLY SOON! LIKE 30 MINS PLS
dmitriy555 [2]

Answer:

Magnitude and Direction is 928 and 44

Step-by-step explanation:

For a Vector w = (x)i+(y)j

The Magnitude of w =\sqrt{x^{2} +y^{2} }

and the Direction of w =tan^{-1}(\frac{y}{x} )

So for our Question , w = - 168i - 160j

Then -4w = -4 (- 168i - 160j) = (-4*-168)i +(-4*-160)j = 672i + 640j

Then the Magnitude of -4w = \sqrt{672^{2} +640^{2} } =928

and the Direction of -4w = tan^{-1}(\frac{640}{672} )=tan^{-1}(\frac{20}{21} )=44 ( to the nearest whole number)

Hope it Helps:)

4 0
2 years ago
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