Answer:
The frequency of the tuning fork is 1760 Hz.
Step-by-step explanation:
Suppose we have a sine function in the following format:

The period is:
![T = \frac{2\pi}{B}{/tex]The frequency, in Hz, is:[tex]F = \frac{1}{T}](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B2%5Cpi%7D%7BB%7D%7B%2Ftex%5D%3C%2Fp%3E%3Cp%3EThe%20frequency%2C%20in%20Hz%2C%20is%3A%3C%2Fp%3E%3Cp%3E%5Btex%5DF%20%3D%20%5Cfrac%7B1%7D%7BT%7D)
In this question:

So

The frequency of the tuning fork is 1760 Hz.
Answer:
I think that is quadratic
5c=y. This is the equation represented in the statement.
Do (6x12)/2, that should work