Answer:ion know
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
It just makes the most sense
Problem
For a quadratic equation function that models the height above ground of a projectile, how do you determine the maximum height, y, and time, x , when the projectile reaches the ground
Solution
We know that the x coordinate of a quadratic function is given by:
Vx= -b/2a
And the y coordinate correspond to the maximum value of y.
Then the best options are C and D but the best option is:
D) The maximum height is a y coordinate of the vertex of the quadratic function, which occurs when x = -b/2a
The projectile reaches the ground when the height is zero. The time when this occurs is the x-intercept of the zero of the function that is farthest to the right.
So we know the slope of the equation because the slope of two parallel lines are the same:
y = -3/2x + b
9 = -3/2( -16 ) + b
9 = 24 + b
b = -15
so the equation of the new line is y = -3/2x - 15