All categories

3 years ago

I bet you 10 points you will not answer this I think its B i need assurance

Mathematics

1 answer:

Flauer [41]3 years ago

5 0

Answer:

(a) seems to be the closest to being correct of these five statements.

Step-by-step explanation:

Let's go through the list of possible descriptors:

a) There are no outliers. This seems to be the response most likely to be correct.

b) The distribution is not skewed left. It's skewed right.

c) The center is not 44. From what I see, the center is 48.

d) This distribution is not bimodal; it does not have two peaks.

d) The spread is not 38 to 67; it's 29 to 67.

You might be interested in

(Giving brainlyiest)<br><br><br> 25 POINTS

o-na [289]

42, 5tc, 2(x+1)/3=42(x+1)/3x6

7 0

2 years ago

If the function f(x) has a domain of (g,h) and a range of (j,k), then what is the domain and range of g(x) = m(f(x)] + p?

sertanlavr [38]

Answer:

$Dom\{g(x)\} = Dom\{f(x)\} = (g, h)$ .

$Ran \{g(x)\} = (m\cdot j+p,m\cdot k +p)$

Step-by-step explanation:

From Mathematics we remember that the domain of a functions corresponds to the set of values of the independent variable ( $x$ in this case) so that images exist and the range of a function is the set of images.

In this case, we know the domain and range of $f(x)$ and we must find the domain and range of $g(x)$ .

Domain

The domain of $g(x)$ is the domain of $f(x)$ . That is, $Dom\{g(x)\} = Dom\{f(x)\} = (g, h)$ .

Range

We have to define the bounds of the range of $g(x)$ , given that range $f(x)$ is modified by streching and horizontal translation operations:

Lower bound ( $f(x) = j$ )

$g(x) = m\cdot j +p$

Upper bound ( $f(x) = k$ )

$g(x) = m\cdot k +p$

In consequence, the range of $g(x)$ is $Ran \{g(x)\} = (m\cdot j+p,m\cdot k +p)$

3 0

3 years ago

The quotient of 2 times a number and 19

Reptile [31]

This one is worded oddly, but I think it's going to be:
(2x)/19

3 0

3 years ago

Read 2 more answers

This is a graph of which linear equation?

Elanso [62]

I think its is 4/5 but not positive

5 0

3 years ago

Somebody please help me Do any that you want you don’t have to do all.

Dmitrij [34]

Answer:

I don't see anything, but I can help you what is it about? If its science. I'm bad at science. If its math I can try to help you.

Step-by-step explanation:

6 0

2 years ago