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rodikova [14]
3 years ago
9

I bet you 10 points you will not answer this I think its B i need assurance

Mathematics
1 answer:
Flauer [41]3 years ago
5 0

Answer:

(a) seems to be the closest to being correct of these five statements.

Step-by-step explanation:

Let's go through the list of possible descriptors:

a) There are no outliers.  This seems to be the response most likely to be correct.

b) The distribution is not skewed left.  It's skewed right.

c) The center is not 44.  From what I see, the center is 48.

d) This distribution is not bimodal; it does not have two peaks.

d) The spread is not 38 to 67; it's 29 to 67.

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Which of the following graphs represents a function
Nata [24]
Where are the graphs? a function is when every input is paired with exactly one output(every x value must have exactly 1 y value). the vertical line test helps determine a function, a vertical line can’t intersect a graph at more then one point, if it does intersect in more then 1 point then it’s not a function
7 0
3 years ago
The liquid volume of Eric's water bottle is 3 liters. What is the approximate liquid volume of 5 of these bottles in milliliters
stepan [7]

Answer:

Option D is correct

The approximate liquid volume of 5 of these bottles is, 15,000 milliliters.

Step-by-step explanation:

Given the statement: The liquid volume of Eric's water bottle is 3 liters.

Using conversion:

1 liters = 1000 milliliters

Convert 3 liters into milliliters;

using above conversion:

3 liters  = 3 \times 1000 = 3000 milliliters.

To find the volume of liquid in 5 of these bottles in milliliters:

Volume of liquid in 1 bottle is, 3000 milliliters.

then;

Volume of liquid in 5 bottles  = 5 \times 3000 = 15,000 milliliters.

Therefore, approximate liquid volume of 5 of these bottles is, 15,000 milliliters

6 0
3 years ago
5.8 times 10 and show work (optional)
Step2247 [10]

Answer:

58

Step-by-step explanation:

A easy way to get this is to remove the decimal in 5.8 which gives you ----> 58

NOTE: This works for any problem multiplying 10 x a decimal.

7 0
3 years ago
17. A hemisphere of lead of radius 7 cm is cast into a right circular cone of height 49 cm. Find
Pavlova-9 [17]

Answer:

r = 3.74cm

Step-by-step explanation:

Given

Hemisphere

Radius = 7cm

Cone

Height = 49m

Required

Determine the radius of the cone

First, we calculate the volume (V1) of the hemisphere.

V_1 = \frac{2}{3}\pi r^3

Substitute 7 for r

V_1 = \frac{2}{3}\pi * 7^3

V_1 = \frac{2}{3}\pi * 343

V_1 = \frac{686}{3}\pi

Volume (V2) of a cone is:

V_2 = \frac{1}{3}\pi r^2h

Because the lead is cast into a cone, then they have the same volume.

So, we have:

\frac{686}{3}\pi = \frac{1}{3}\pi r^2h

686 =  r^2h

Substitute 49 for h

686 =  r^2 * 49

Divide both sides by 49

r^2 = \frac{686}{49}

r^2 = 14

r = \sqrt{14

r = 3.74cm

<em>Hence, the radius of the cone is 3.74cm</em>

5 0
3 years ago
What would be the answer to this math problem
galben [10]
Pi is a irrational number.
HOPE THIS HELPS! ^_^
8 0
3 years ago
Read 2 more answers
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