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3 years ago

Help??? 20 Points

Mathematics

1 answer:

Dominik [7]3 years ago

4 0

1. No; it is not written as a number times the power of 10.

2. 1.22×10^9

3. 2.87×10^−2

4. 5000

5. is answered in attached picture.

6. 3.212×10^3

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Parallel lines t and u are cut by two transversals, r and s, which intersect line u at the same point.

Bezzdna [24]

Answer:

Step-by-step explanation:

it was right on edge

8 0

3 years ago

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Replace the * with a monomial so that the trinomial may be represented by a square of a binomial:

pogonyaev

Answer:

Below in bold.

Step-by-step explanation:

The identity is of the form

(a + b)^2 = a^2 + 2ab + b^2.

a) Sqrt 49 = 7 and we need + 28 as the middle coefficient . We get this with

2*7 + 2*7 so the first coefficient is 2*2 = 4.

So * = 4a^2.

(2a + 7)^2 = (2a + 7)(2a + 7) = 4x^2 + 14a + 14a + 49.

b) -6 * -6 = 36 -24 = 2*-6 + 2 *-6 so the last term is 4x^2

c) The middle term must be an 'ab' term.

sqrt 6.25 = 2.5 and sqrt 1/4 = 1/2

So the coefficient of the middle term is 2.5 * 1/2 + 2.5 * 1/2

= 2.5

So the middle term is 2.5ab.

d) The first term will be in b^2.

100 = 10* 10 and we need 2 as a middle term so coefficient of the first term

will be 1/100 or 0.01. as the 2 comes from 0.1 * 10 + 0.01 * 10 and (0.1)^2 = 0.01

So it is 0.01b^2.

8 0

3 years ago

Hilary Unraveled 3.0 centimeters of ribbon then continued to unravel 1.5 more centimeters. Which horizontal number line could be

Snezhnost [94]

<u>Answer:</u>

The horizontal number line that could be used to show number of centimeters of ribbon Hilary unraveled is 3cm to 4.5cm

<u>Explanation:</u>

Given that Hilary has already unraveled 3.0 centimeters of ribbon and then continues to unravel 1.5 more.

So starting will be 3.0 cm and maximum ribbon unravelled will be equal to 4.5cm so the horizontal number line that could be used would be from 3cm to 4.5cm including both fractional and integral values.

6 0

3 years ago

Read 2 more answers

How do you write 6,007,200 in two other forms

miskamm [114]

Six million and seventy two hundred. 6.0072 x 10*

*=6

3 0

4 years ago

SCALCET8 3.9.017.MI. Two cars start moving from the same point. One travels south at 48 mi/h and the other travels west at 20 mi

Veronika [31]

Answer:

The rate at which the distance between the cars increasing two hours later=52mi/h

Step-by-step explanation:

Let

Speed of one car, x'=48 mi/h

Speed of other car, y'=20 mi/h

We have to find the rate at which the distance between the cars increasing two hours later.

After 2 hours,

Distance traveled by one car

$x=48\times 2=96 mi$

Using the formula

$Distance=Time\times speed$

Distance traveled by other car

$y=20\times 2=40 mi$

Let z be the distance between two cars after 2 hours later

$z=\sqrt{x^2+y^2}$

Substitute the values

$z=\sqrt{(96)^2+(40)^2}$

z=104 mi

Now,

$z^2=x^2+y^2$

Differentiate w.r.t t

$2z\frac{dz}{dt}=2x\frac{dx}{dt}+2y\frac{dy}{dt}$

$z\frac{dz}{dt}=x\frac{dx}{dt}+y\frac{dy}{dt}$

Substitute the values

$104\frac{dz}{dt}=96\times 48+40\times 20$

$\frac{dz}{dt}=\frac{96\times 48+40\times 20}{104}$

$\frac{dz}{dt}=52mi/h$

Hence, the rate at which the distance between the cars increasing two hours later=52mi/h

3 0

3 years ago

Help??? *****20 Points*****

Help??? 20 Points