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4vir4ik [10]
3 years ago
8

Find the slope of this table.

Mathematics
1 answer:
trasher [3.6K]3 years ago
6 0

Answer:

-6/2 = Slope = - 3

Step-by-step explanation: Hope this helps!

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There were 16 sandwiches on a tray for a lunch meeting. After the meeting, 3 were left. How many sandwiches were eaten?
kifflom [539]

Answer:

13

Step-by-step explanation:

16-3+= 13

6 0
3 years ago
Which undefined terms are needed to define parallel lines
Alexandra [31]
Parallel lines<span> are coplanar </span>lines<span> that do not intersect</span>
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What is the circumference of the circle in the example? 2π 4π 6π
ale4655 [162]

Answer:vssbiubpu buivbub [u bu[b [uib

Step-by-step explanation:

scewsucpsivgeduaigxuygu1yuwgyugvuygquyy3gvdv

3 0
3 years ago
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A high school football team won 80% of the games they played. If they played 35 games, how many games did they win?
crimeas [40]

Step-by-step explanation:

formuale \\ \%wom = total \: win \:  \times 100\% \div total \: matches \: played

let x be total much won

80\% = x \times 100\% \div 35 \\  x= 35 \times 80 \div 100 \\ x = 7 \times 4 \\ x = 28

so they team had won 28 matches.

I hope the team has best players : )

8 0
3 years ago
What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as
Andrej [43]

Complete question :

Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.

What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.

Answer:

0.56 ; 0.60

Step-by-step explanation:

From The attached Venn diagram :

C = attend college ; J = has a job

P(C) = (35+45)/300 = 80/300 = 8/30

P(J) = (30+45)/300 = 75/300 = 0.25

P(C n J) = 45 /300 = 0.15

1.)

P(J | C) = P(C n J) / P(C)

P(J | C) = 0.15 / (8/30)

P(J | C) = 0.5625 = 0.56

2.)

P(C | J) = P(C n J) / P(J)

P(C | J) = 0.15 / (0.25)

P(C | J) = 0.6 = 0.60

5 0
2 years ago
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