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3 years ago

The product of a number and 2/3 is 9/10. What is the number?

Mathematics

2 answers:

Tema [17]3 years ago

5 0

Answer:

The product is the answer to a multiplication problem. You can find a product by a process called repeated addition, which is to say, by adding together the number of groups in the problem.

Step-by-step explanation:

Arlecino [84]3 years ago

4 0

Answer:

$\frac{27}{20}$

Step-by-step explanation:

To find the number we can do the inverse operation to find it:

$\frac{2}{3}$ × n = $\frac{9}{10}$ - so we divide as an inverse function

$\frac{9}{10}$ ÷ $\frac{2}{3}$ = 27/20

You might be interested in

Write a polynomial function with zeros -3,5,8

klemol [59]

Answer:

x^3-10x^2+x+120

Step-by-step explanation:

Assuming you mean roots -3, 5, 8

These happen when we have (x+3)(x-5)(x-8)=0

Expand this

(x^2-2x-15)(x-8)=0

=x^3-2x^2-15x-8x^2+16x+120

=x^3-10x^2+x+120

3 0

2 years ago

its 76 degrees fahrenheit at the 6000-foot level of a mountain, and 49 degrees Fahrenheit at the 12000-foot level of the mountai

brilliants [131]

$T = \frac{-9}{2}x + 103$ is the linear equation to find the temperature T at an elevation x on the mountain, where x is in thousands of feet.

Solution:

The linear equation in slope intercept form is given as:

T = cx + k ------ (i)

Where "t" is the temperature at an elevation x

And x is in thousands of feet

Given that its 76 degrees fahrenheit at the 6000-foot level of a mountain

Given, when c = 6 thousand ft and $T = 76^{\circ}$ fahrenheit

This implies,

From (i)

76 = c(6) + k

76 = 6c + k

⇒ k = 76 - 6c ----- (ii)

Given that 49 degrees Fahrenheit at the 12000-foot level of the mountain

Given, when c = 12 thousand ft and $T = 49^{\circ}$ fahrenheit

This implies,

From (i)

49 = c(12) + k

49 = 12c + k

Substitute (ii) in above equation

49 = 12c + (76 - 6c)

49 = 12c + 76 - 6c

49 - 76 = 6c

6c = -27

$c = \frac{-9}{2}$

Substituting the value of c in (ii) we get

$k = 76 - 6( \frac{-9}{2})\\\\k = 76 + 27 = 103$

Substituting the value of c and k in (i)

$T = \frac{-9}{2}x + 103$

Where "x" is in thousands of feet

Thus the required linear equation is found

5 0

3 years ago

Which pair of expressions is equivalent?

riadik2000 [5.3K]

You’re answer is a
Please mark brainliest

4 0

3 years ago

How much water should you have in a severe weather emergency supply kit?

Y_Kistochka [10]

Answer: u should have at least i gallon per person per day

8 0

2 years ago

If p=(-3,-2) and q=(1,6) are the endpoints of the diameter of a circle find the equation of the circle

stira [4]

Answer:

The equation of the circle (x +1) )² +(y-(2))² = (2(√5))²

 or 

The equation of the circle x² + 2 x + y² - 4 y = 15

Step-by-step explanation:

Given points end Points are p(-3,-2) and q( 1,6)

The distance of two points formula

P Q = $\sqrt{x_{2} - x_{1})^{2} + ((y_{2} -y_{1})^{2} }$

P Q = $\sqrt{1 - (-3)^{2} + ((6 -(-2))^{2} }$

P Q = $\sqrt{16+64} = \sqrt{80}$

The diameter 'd' = 2 r

2 r = √80

= $\sqrt{16 X 5}$

= $4 \sqrt{5}$

r = 2√5

Mid-point of two end points

$(\frac{x_{1} + x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) = (\frac{-3+1}{2} ,\frac{-2 +6}{2} )$

= (-1 ,2)

Mid-point of two end points = center of the circle

(h,k) = (-1 , 2)

The equation of the circle

(x -h )² +(y-k)² = r²

(x -(-1) )² +(y-(2))² = (2(√5))²

x² + 2 x + 1 + y² - 4 y + 4 = 20

x² + 2 x + y² - 4 y = 20 -5

x² + 2 x + y² - 4 y = 15

Final answer:-

The equation of the circle (x +1) )² +(y-(2))² = (2(√5))²

 or 

The equation of the circle x² + 2 x + y² - 4 y = 15

6 0

3 years ago