Answer:
2.4 g
Explanation:
Step 1: Given data
- Initial pressure (P₁): 755 torr
- Final pressure (P₂): 1.87 atm
Step 2: Convert "P₁" to atm
We will use the conversion factor 1 atm = 760 torr.
755 torr × 1 atm/760 torr = 0.993 atm
Step 3: Convert "T" to K
We will use the following expression.
K = °C + 273.15
K = 25°C + 273.15 = 298 K
Step 4: Calculate the initial number of moles of He
We will use the ideal gas equation.
P₁ × V = n₁ × R × T
n₁ = P₁ × V/R × T
n₁ = 0.993 atm × 16.8 L/(0.0821 atm.L/mol.K) × 298 K
n₁ = 0.682 mol
Step 5: Calculate the final number of moles of He
We will use the ideal gas equation.
P₂ × V = n₂ × R × T
n₂ = P₂ × V/R × T
n₂ = 1.87 atm × 16.8 L/(0.0821 atm.L/mol.K) × 298 K
n₂ = 1.28 mol
Step 6: Calculate the moles of He added
n = n₂ - n₁
n = 1.28 mol - 0.682 mol
n = 0.60 mol
Step 7: Convert "n" to mass
The molar mass of He is 4.00 g/mol
0.60 mol × 4.00 g/mol = 2.4 g
Correct Answer: option C:The pair which consist of molecules having the same geometry is CH2CCI2 and CH2CH2.
Reason:
Both of the above molecules contain double bonds. They are characterized by sp^2 hybridization. Also, they possess a trigonal planar geometry. In trigonal planar system, the molecule consist of three equally spaced sp^2 hybrid orbitals, which arranged at angle 120 degree.
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Answer:
132g/mol
Explanation:
The problem here is to find the molar mass of the compound in g/mol
To solve this problem, we simply sum the atomic masses of the atoms in the compound:
(NH₄)₂ SO₄:
Atomic mass of N = 14g
Atomic mass of H = 1g
Atomic mass of S = 32g
Atomic mass of O = 16g
So;
Molar mass = 2[(14 + 4(1))] + 32 + 4(16) = 132g/mol
