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NemiM [27]
4 years ago
8

In looking at the bolded atoms in the answer choices, which pair consists of molecules having the same geometry?

Chemistry
2 answers:
ICE Princess25 [194]4 years ago
7 0
Correct Answer: option C:The pair which consist of molecules having the same geometry is CH2CCI2 and CH2CH2.

Reason: 
Both of the above molecules contain double bonds. They are characterized by  sp^2 hybridization. Also, they possess a trigonal planar geometry. In trigonal planar system, the molecule consist of three equally spaced sp^2 hybrid orbitals, which arranged at angle 120 degree. 

Over [174]4 years ago
7 0

The choices given were:

PCl3 and BF3

CH2O and CH3OH

CH2CCl2 and CH2CH2

CO2 and SO2

The correct option is CH2CCl2 and CH2CH2 because both of them contains a double bond which is sp^2 hybridized and it shows a trigonal planar geometry.

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That will make a gold-202 nucleus.

<h3>Explanation</h3>

Refer to a periodic table. The atomic number of mercury Hg is 80.

Step One: Bombard the \displaystyle ^{202}_{\phantom{2}80}\text{Hg} with a neutron ^{1}_{0}n. The neutron will add 1 to the mass number 202 of ^{202}_{\phantom{2}80}\text{Hg}. However, the atomic number will stay the same.

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^{202}_{\phantom{2}80}\text{Hg} + ^{1}_{0}n \to ^{203}_{\phantom{2}80}\text{Hg}.

Double check the equation:

  • Sum of mass number on the left-hand side = 202 + 1 = 203 = Sum of mass number on the right-hand side.
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Step Two: The ^{203}_{\phantom{2}80}\text{Hg} nucleus loses a proton ^{1}_{1}p. Both the mass number 203 and the atomic number will decrease by 1.

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^{203}_{\phantom{2}80}\text{Hg} \to ^{202}_{\phantom{2}79}\text{Au} + ^{1}_{1}p.

Double check the equation:

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  • Sum of atomic number on the left-hand side = 80 = 79 + 1 = Sum of atomic number on the right-hand side.

A gold-202 nucleus is formed.

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