Question

The specific heat capacity of water is 4.186 J/g °C

Answer 1

Answer:

Q

C= M×∆T

Explanation:

Energy (Q) J

Change of temperature (ΔT) °C

Mass (m) kg

Substance (optional) Custom ▾

Specific heat capacity (c) J/(kg·K)

HOPE IT HELPS

Answer 2

Answer:

Solution given:

specific heat capacity of water [c]4.186 J/g °C

temperature[∆T]=?

mass[m]=3g

heat[Q]=8000J

we have

Q=mc∆T

8000=3*4.186*∆T

∆T=8000/12.558

∆T=637.04°C

the temperature change is 637.04°C.