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Arturiano [62]
3 years ago
14

The specific heat capacity of water is 4.186 J/g °C

Chemistry
2 answers:
Serggg [28]3 years ago
5 0

Answer:

<h2> Q</h2><h2> C= M×∆T</h2>

Explanation:

Energy (Q) J

Change of temperature (ΔT) °C

Mass (m) kg

Substance (optional) Custom ▾

Specific heat capacity (c) J/(kg·K)

HOPE IT HELPS

erastovalidia [21]3 years ago
3 0

Answer:

Solution given:

specific heat capacity of water [c]4.186 J/g °C

temperature[∆T]=?

mass[m]=3g

heat[Q]=8000J

we have

Q=mc∆T

8000=3*4.186*∆T

∆T=8000/12.558

∆T=637.04°C

<u>the temperature </u><u>change</u><u> </u><u>i</u><u>s</u><u> </u><u>637.04°</u><u>C</u><u>.</u>

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a 22.44g sample of iron absorbs 180.8 J of heat, upon which the temperature of the sample increases from 21.1C to 39.0/ what is
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Answer:

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Explanation:

The amount of heat absorbed by the metal is given by:

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From the data, we have:

heat = 180.8 J

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Thus, we calculate the specific heat of iron (Sh) as follows:

Sh = heat/(m x ΔT)  = (180.8 J)/(22.44 g x 17.9°C) = 0.45 J/g.°C

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The sample response given in the question is right.

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