Question

Complete the table below using the Midpoint and Distance Formulas.

Answer 1

Answer:

Coordinates of M = (2, -1)

Length of AB = 10 units

Step-by-step explanation:

Coordinates of the midpoint (M) of the distance between A(2, 4) and B(2, -6)

$M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})$

Let $A(2, 4) = (x_1, y_1)$

$B(2, -6) = (x_2, y_2)$

Thus:

$M(\frac{2 + 2}{2}, \frac{4 +(-6)}{2})$

$M(\frac{4}{2}, \frac{-2}{2})$

$M(2, -1)$

Length of AB:

Distance between A(2, 4) and B(2, -6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(2, 4) = (x_1, y_1)$

$B(2, -6) = (x_2, y_2)$

$AB = \sqrt{(2 - 2)^2 + (-6 - 4)^2}$

$AB = \sqrt{(0)^2 + (-10)^2}$

$AB = \sqrt{0 + 100} = \sqrt{100}$

$AB = 10$