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3 years ago

In business terms, the word agreement is equivalent to the word _____.

2 answers:

8 0

<span>In business terms, the word agreement is equivalent to the word contract. The correct option among all the options that are given in the question is the third option or option "C". A contract is basically a kind of legal binding. I hope that this answer has actually come to your great help.</span>

Ahat [919]3 years ago

8 0

In business terms, the word agreement is equivalent to the word "contract". APEX confirmed!

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What is the probability that a passenger prefers to sit in front of the plane and prefers a window seat

Ksenya-84 [330]

Answer:

Step-by-step explanation:

This is a probability question.

We want to calculate the probability that a passenger prefers to sit in front of the plane and at a window seat.

The answer here is directly obtainable from the table. Let’s take a look at that point where we have the front and window merging. We can see that the figure here is 8

Thus, the probability that we want to calculate is this figure over the total = 8/36

= 2/9

6 0

3 years ago

Read 2 more answers

The equation of a circle is (x+2)2 + (y-3)2 =9. What are the coordinates of the center of this circle?

Setler [38]

Answer:

Step-by-step explanation:

center is (-2,3)

6 0

3 years ago

HELP I NEED HELP ASAP

victus00 [196]

Answer: (5, -2)

Step-by-step explanation:

$y= x-7\\2x+y=8$

Substitute x-7 for y in 2nd equation

$2x+ x-7 =8\\3x-7=8\\3x = 15\\x=5$

Solve for y

$y=5-7\\y=-2$

8 0

3 years ago

There are 200 students in the 8th grade class at Alleghany Middle School. Of these students, 8% play basketball and 14% play soc

sergeinik [125]

Answer:

The probability that a student plays either basketball or soccer is 19% or 0.19.

Step-by-step explanation:

Let A be the event that student play basketball and B be the event that student play soccer.

$P(A)=8\%$

$P(B)=14\%$

It is given that 6 students play on both teams.

$P(A\cap B)=\frac{6}{200}\times 100=3\%$

We have to find the probability that a student plays either basketball or soccer.

$P(A\cup B)=P(A)+P(B)-(A\cap B)$

$P(A\cup B)=8\%+14\%-3\%$

$P(A\cup B)=19\%$

Therefore the probability that a student plays either basketball or soccer is 19% or 0.19.

6 0

4 years ago

Can someone please help me!!

Elan Coil [88]

Answer:

Step-by-step explanation:

Firstly we would start off by simplifying the equation by doing the order of operations backward (PEMDAS -> SADMEP) and multiply -4 and -3 which would equal a positive 12

Next, we would divide 12 and -6 and get a negative 2

Finally, we would have the equation 1 - 12 + (-2)

We would solve the equation to get -13/(-1)³

This would make the -13 into a positive since any number over one is a whole number. -13 is getting divided by (-1) 3 times so it converts to a positive, then a negative, then back to a positive.

I hope this helped :3

6 0

3 years ago